remove elements from cell

Dear all, I know, I've asked alot and I really appreciate your help. I have a cell array:

a = {[1 2 3 55  77 8] [3 77] [ 1 2 5 7 8 9 0 2] [ 3 44 6]}

and I would like to remove the numbers before the index based on vector b=[3 9 6]. The expected answer should be:

cell2 = {[55 77 8] [77] [0 2] []}

Thanks.

[Jan]

It is very welcome if you ask many questions here. But it would be appreciated, if you explain the problem as detailed as needed to define it uniquely. The explanation "remove the numbers before the index based on vector b=[3 9 6]" is not clear. Then showing any own effort and asking a specific question concerning your code would be useful also, for you and for the readers.

Answer 1

[Image Analyst]

This will do it:

a = {[1 2 3 55  77 8] [3 77] [ 1 2 5 7 8 9 0 2] [ 3 44 6]}
b=[3 9 6]
% cell2 = {[55 77 8] [77] [0 2] []}
for k = 1 : length(a)
  thisArray = a{k}; % Extract array from cell.
  [inA, inB] = ismember(b, thisArray); % Find where any of b occurs in thisArray.
  index = find(inB>0, 1, 'last'); % Find last occurrence.
  outputArray = thisArray(inB(index)+1:end); % Extract out to new array.
  cell2{k} = outputArray; % Stuff into a new cell array.
end
celldisp(cell2); % Display in command window.

It's easy and intuitive, though I'm sure someone will give you a cryptic one-liner shortly.

[skysky2000]

thanks, but this is not work with my situation

[dbmn]

skysky could you tell us what didnt work in your case?

image_analyst: one liner coming up

cell2 = cellfun(@(x) x(max([find(ismember(x, b),1, 'last'), 0])+1:end), a, 'uni', 0);

p.s. when you use max([index, 0]) you can get rid of the empty matrices :)

[skysky2000]

thanks alot dbmn for your help

Answer 2

[skysky2000]

any help please?

[Image Analyst]

I gave you help. My code produced exactly the cell array that you said you wanted. What's the problem? Prove to me that it does not give you what you asked for, because I don't know what else to do.

[Jan]

@skysky2000: Please do not bump your thread by posting a pseudo-answer. The question is not really clear, but Image Analysts has posted a method to produce the requested answer. Now it is your turn to explain, which details is not solved yet.