Maintain shape of logical index mask

I have a matrix A=[1,2,3;4,5,6]. From this, I want to remove (by row), z=[1,5], to return the matrix B=[2,3;4,6]. I'm trying to use logical indexing to do this, but that returns a vector instead of the matrix B.

if true
  B=A(A~=z(:,1))
end

Answer 1

[Andrei Bobrov]

   Aout = A';
   Aout = reshape(Aout(Aout ~= z(:)'),[],2)';

or

   Aout = A';
   Aout = reshape(Aout(~ismember(Aout,z)),[],2)';

[Garima Sharma]

Thanks, this works!