Extract data based on columns
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Altruists,
I have the data in the following matrix.
Year month value
2000 1 10
2000 2 20
2000 3 30
I have to extract this values to the following matrix in repetition, for example:
Year month value
2000 1 ?
2000 1 ?
2000 2 ?
Thanks
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Answers (2)
Walter Roberson
on 5 Jun 2017
Edited: Walter Roberson
on 5 Jun 2017
YourMatrix = [2000 1 10
2000 2 20
2000 3 30];
probe_rows = [2000 1
2000 1
2000 2];
[uniqYM, ~, uniq_rowidx] = unique(YourMatrix(:,1:2), 'rows', 'stable');
[tf, index_in_uniqYM] = ismember(probe_rows, uniqYM, 'rows');
valid_idx_in_uniqYM = index_in_uniqYM(tf);
output = YourMatrix( ismember(uniq_rowidx, valid_idx_in_uniqYM), :);
Note: this code was specifically designed with the possibility that the year and month entries in the original matrix might not be unique, that you might need to retrieve multiple rows.
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Walter Roberson
on 5 Jun 2017
YourMatrix = [2000 1 10
2000 2 20
2000 3 30];
probe_rows = [2000 1
2000 1
2000 2];
[tf, index_in_original] = ismember(probe_rows, YourMatrix(:, [1 2]), 'rows');
output = YourMatrix( index_in_original(tf), : );
Guillaume
on 5 Jun 2017
If your matrices are actually tables as your formatting sort of imply, then it's trivially done with join or outerjoin (depending on whether or not you want to include rows that don't match:
%inputs as table:
data = table([2000; 2000; 2000], [1; 2; 3], [10; 20; 30], 'VariableNames', {'year', 'month', 'value'})
probe = table([2000; 2000; 2000], [1; 1; 2], 'VariableNames', {'year', 'month'});
%include only rows that match
result = join(probe, data)
%include rows of probe that do not match
result = outerjoin(probe, data, 'Type', 'left');
If your inputs are actually matrices, then convert them to tables or use Walter's answer.
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