How can i create matrix automatically?

Hi everbody

I should create a matrix by using number of element of any gap like as the example:

If gap has:

3 elements, matrix: [1 1 2]

4 elements, matrix: [1 1 2 2]

7 elements, matrix: [1 1 2 2 3 3 4] etc.

and matrix includes only 1 2 3 4 numbers, same numbers must be two side by side.

Is there any way for this operation?

Thanks...

Edit:

I have just created a loop for this operation:

for ...
  elements=[1 1 2 2 3 3 4 4];
  if numel(gap)<=numel(elements);
     matrix=elements(1:numel(gap));
  end
  if numel(gap)>numel(elements);
     diff=(numel(gap)-numel(elements))
     matrix=[elements linspace(4,4,diff)]
  end
end

Answer 1

[Stephen23]

>> fun = @(n)ceil((1:n)/2);
>> fun(3)
ans =
   1   1   2
>> fun(4)
ans =
   1   1   2   2
>> fun(7)
ans =
   1   1   2   2   3   3   4

[Volkan Yangin]

Thank you Stephen Cobeldick. By the time i have just created if-end loop for this operation and added under the your comment.

Answer 2

[Volkan Yangin]

for ...
  elements=[1 1 2 2 3 3 4 4];
  if numel(gap)<=numel(elements);
     matrix=elements(1:numel(gap));
  end
  if numel(gap)>numel(elements);
     diff=(numel(gap)-numel(elements))
     matrix=[elements linspace(4,4,diff)]
  end
end