# I am struggling with a code.the code for signal transmition in Non Orthogonal Multiple Access. Please help me.

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clc;

clear all;

n=100;%n0.0f bits for transmit signal

ds1=2;%distance from BS to su1

dp=3;%distance from BS to pu

ds2=4;%distance from BS to su2

%%%the signal from the BS

xp=rand(1,n)>0.5;

xs1=rand(1,n)>0.2;

xs2=rand(1,n)>0.3;

X=xp+xs1+xs2;

%%%the signal received @the su1

for s=0.1:0.01:1%noise variation

N=s*randn(1,n);

ys1=xs1/ds1.^2+N+xp/dp.^2+xs2/ds2.^2

end

##### 5 Comments

Walter Roberson
on 28 Nov 2020

ahmad almuhands:

This facility exists to assist people in learning MATLAB, and helping them debug problems. We do not write programs for people (unless the programs are very small.)

### Accepted Answer

Axel Moor
on 1 Nov 2017

I hope the code below could be of some help. Regards to you all.

clc;

clear all;

%=============================================================================

%=============================================================================

% Non Orthogonal Multiple Access (NOMA) Simulation

% Version 1: Encode only: Transmitter side, no modulation

%=============================================================================

% This code was based on codes made by Simith (SMT) and Thanh Nguyen (TNY)

% published in:

% Website: MathWorks (R) - www.mathworks.com

% Forum: MATLAB Answers [TM] - /matlabcentral/answers/

% Title: I am struggling with a code.the code for signal transmition in

% Non Orthogonal Multiple Access. Please help me.

% Asked: simith on 15 Mar 2017 - SMT

% Answer: Thanh Nguyen on 21 Apr 2017 - TNY

%=============================================================================

%=============================================================================

%=============================================================================

% Variable Names:

% Variable names were changed according to a notation 'similar' to the

% 'Hungarian Notation' and structured programming for better

% understanding of NOMA techniques since many MATLAB Users are not use

% to the meaning of equation variables related to NOMA mathematics.

%

% +--------- new NOMA variable name

% |

% +---+---+

% VarName_XXX

% +-+-+

% |

% +--- original SMT/TNY variable name,

% '_00' if the variable isn't in SMT/TNY codes

%=============================================================================

% n0.0f bits for transmit signal: 4 bits only - REMOVE '/25' for 100 bits

% as original SMT/TNY codes;

TxBits_n = 100/25;

% distance from Base Station (BS) to Primary User, to User1, to User2 - SMT

% Assuming maximum distance as 10, for attenuation calculation purposes

DstBStoPUser_dp = 3;

DstBStoUser1_ds1 = 2;

DstBStoUser2_ds2 = 4;

MaxDsttoUser_00 = 10;

SumSquareDst_00=DstBStoPUser_dp^2+DstBStoUser1_ds1^2+DstBStoUser2_ds2^2;

% signal from BS - Power allocation already applied on signal(???) - SMT:

% xp=rand(1,n)>0.5;

% xs1=rand(1,n)>0.2;

% xs2=rand(1,n)>0.3;

%

% power allocation for Primary User, User1 and User 2 - TNY:

% pp=0.5;

% p1=0.3; inverse from SMT: p1<->p2

% p2=0.2; inverse from SMT: p1<->p2

%

% NOMA corrected: farther away from Base Station (BS), more allocated power;

% Assuming the Base Station (BS) has total power of 1 and will allocate

% power for each User as proportional to squared distance: Pwr ~ Dst^2

%

TotPwrBS_00 = 1.0;

% previously suggested: 0.3

PwrPUser_pp = TotPwrBS_00*(DstBStoPUser_dp^2)/SumSquareDst_00;

% previously suggested: 0.2

PwrUser1_p1 = TotPwrBS_00*(DstBStoUser1_ds1^2)/SumSquareDst_00;

% previously suggested: 0.5

PwrUser2_p2 = TotPwrBS_00*(DstBStoUser2_ds2^2)/SumSquareDst_00;

%=============================================================================

%%%Create random binary messages/signals from Base Station (BS)

%=============================================================================

% signal of 'n' bits from BS to Primary User, User1 and User2 based on

% with power allocation already applied??? - SMT:

% xp=rand(1,n)>0.5;

% xs1=rand(1,n)>0.2;

% xs2=rand(1,n)>0.3;

% signal stream of Primary User, User1 and User2 - TNY:

% 'rand' generates any number between [0 and 1], NOT binary, noise included???

% xp=rand(1,n);

% xs1=rand(1,n);

% xs2=rand(1,n);

%

% Correct (actual) binary messages of 'TxBits_n' bits length:

% equal probability of 0 and 1 in every bit;

% 'rand' generates numbers in [0 to 1], uniformally distributed;

% Mean is 0.5

%

SgnPUser_xp = rand(1,TxBits_n) > 0.5;

SgnUser1_xs1 = rand(1,TxBits_n) > 0.5;

SgnUser2_xs2 = rand(1,TxBits_n) > 0.5;

%=============================================================================

%%%Superposition Encoding

%=============================================================================

% Direct sum of signals: incorrect - SMT: X=xp+xs1+xs2;

% NOMA: Power-domain Multiplexing, sum of products signal*sqrt(power) - TNY:

%

Enc_X = sqrt(PwrPUser_pp)*SgnPUser_xp;

Enc_X = sqrt(PwrUser1_p1)*SgnUser1_xs1 + Enc_X;

Enc_X = sqrt(PwrUser2_p2)*SgnUser2_xs2 + Enc_X;

%=============================================================================

%%%Received signals for all Users

%=============================================================================

% Adding Gaussian Noise: use 'randn' instead of 'rand':

% 'randn' generates numbers in [-Inf,+Inf], normally distributed (Gaussian);

% Mean is zero, but with strong concetration in [-1 to +1];

% 'rand' generates numbers in [0 to 1], uniformally distributed;

% Mean is 0.5

%

% NOMA: Additive White Gaussian Noise (AWGN) with ZERO MEAN and double-side

% power spectral density, N0/2.

% Noise variation on time N(t) (addition): different for every bit;

%

% Since 'randn' concetrates in [-1 to +1] or even larger and a bit is only

% [0 or 1], and Power<=1 the Signal-to-Noise Ratio (SNR) could be too low.

% So a constant to reduce Noise level is necessary.

%

NoiseReduc_0 = 10;

NoisePUser_N = randn(1,TxBits_n)/NoiseReduc_0;

NoiseUser1_N = randn(1,TxBits_n)/NoiseReduc_0;

NoiseUser2_N = randn(1,TxBits_n)/NoiseReduc_0;

% Channel Attenuation Gain (multiplier): different for every User/channel,

% no variation on time. Attenuation is inversely proportional to the power

% and directly proportional to squared distance.

% As the allocated power is proportional to squared distance: Pwr ~ Dst^2,

% it makes all Attenuations become a "boring" constant (0.71 in this case).

% So a random System Loss inversely proportional to power was included to

% increase the unpredictability of simulation.

%

SyLosPUser_00 = 1 + rand/(10*PwrPUser_pp);

AtnGnPUser_00 = TotPwrBS_00/PwrPUser_pp * 1/SyLosPUser_00;

AtnGnPUser_00 = AtnGnPUser_00*(DstBStoPUser_dp^2)/(MaxDsttoUser_00^2);

AtnGnPUser_00 = 1 - AtnGnPUser_00;

SyLosUser1_00 = 1 + rand/(10*PwrUser1_p1);

AtnGnUser1_00 = TotPwrBS_00/PwrUser1_p1 * 1/SyLosUser1_00;

AtnGnUser1_00 = AtnGnUser1_00*(DstBStoUser1_ds1^2)/(MaxDsttoUser_00^2);

AtnGnUser1_00 = 1 - AtnGnUser1_00;

SyLosUser2_00 = 1 + rand/(10*PwrUser2_p2);

AtnGnUser2_00 = TotPwrBS_00/PwrUser2_p2 * 1/SyLosUser2_00;

AtnGnUser2_00 = AtnGnUser2_00*(DstBStoUser2_ds2^2)/(MaxDsttoUser_00^2);

AtnGnUser2_00 = 1 - AtnGnUser2_00;

%=============================================================================

%%%Signal received by each User

%=============================================================================

% SMT: bit-lenght iteraction adding a Noise, increasing per bit - incorrect;

% Adding signal/(squared distance) - incorrect;

% for s=0.1:0.01:1 % noise variation

% N=s*randn(1,n);

% ys1=xs1/ds1.^2+N+xp/dp.^2+xs2/ds2.^2

% end

%

% NOMA: the Superposition Encoding (Enc_X) containing the messages to all

% Users already calculated above is affected by Attenuation (multiplier) and

% Noise (additive) just one time only as in Linear equation below:

%

% Yk(t) = X(t).Gk + Wk(t) where

%

% Yk(t) = superimposed signal received by User[k];

% X(t) = superimposed signal with all Users messages as transmitted by BS;

% Gk = channel attenuation gain for the link between BS and User[k];

% Wk(t) = additive White Gaussian Noise (AWGN) at the User[k] with

% mean ZERO and density N0;

%

RxSgnPUser_ysp = Enc_X*AtnGnPUser_00 + NoisePUser_N;

RxSgnUser1_ys1 = Enc_X*AtnGnUser1_00 + NoiseUser1_N;

RxSgnUser2_ys2 = Enc_X*AtnGnUser2_00 + NoiseUser2_N;

##### 11 Comments

Sami Hadeyya
on 31 Mar 2020

Edited: Sami Hadeyya
on 31 Mar 2020

Dear Moor

please share Energy-Spectral Efficiency Tradeoff of Downlink

NOMA System with Fairness Consideration if you have

### More Answers (5)

Tahir Arshad
on 1 May 2018

hello sir, can you please share the matlab code for NOMA specially receiver side. thanks

##### 0 Comments

Sami Hadeyya
on 31 Mar 2020

Dear Thanh Nguyen

please share Energy-Spectral Efficiency Tradeoff of Downlink

NOMA System with Fairness Consideration if you have

##### 0 Comments

Thanh Nguyen
on 21 Apr 2017

I am not sure whether my answer can help you about the NOMA.

Firstly, generate the bit sequences for each user separately and then modulate them by a common modulation scheme like QPSK. In this step, the signal for each users is considered equally in power.

Secondly, combine the signals into one stream (I call NOMA modulation in power domain, or in some papers they call Superposition Encoding). In this step, we have to consider the Power Allocation for each user s' signal (reference to others NOMA papers for more detail).

Finally, the sole signal will be transmitted as the same way as you described.

Let consider my suggested pseudo code:

clc;

clear all;

n=100;%n0.0f bits for transmit signal

%%%the signal from the BS

xp=rand(1,n); % signal stream of primary user

pp=0.5; % power allocation for primary user

xs1=rand(1,n); % signal stream of user 1

p1=0.3; % power allocation for user 1

xs2=rand(1,n); % signal stream of user 2

p2=0.2; % power allocation for user 2

%superposition encoding

X=sqrt(pp)*xp+sqrt(p1)*xs1+sqrt(p2)*xs2;

##### 8 Comments

shardul thapliyal
on 8 Jun 2020

simith
on 24 Nov 2017

##### 2 Comments

Daniel Demessie
on 9 Apr 2019

if there is matlab code for power allocation for non orthogonal multiple access

please send it

Daniel Demessie
on 9 Apr 2019

##### 1 Comment

Jan
on 10 Apr 2019

This is not answer to the question. Please do not hijack other threads by posting pseudo-answers.

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