??? Error using ==> reshape Size can only have one unknown dimension. Error in ==> SpatialMod at 5 x1 = reshape(bi​t_T,Nobit+​Nt,[]);

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when i try to run the program getting the above mentioned error. how to correct it.
function simulation_of_SM_iMRC()
global M Mt hmodem bit_T
clear all;
clear UnUsEdVaRiAbLe_To_IgNoRe;
clc;
mode = 1;
M = 16;
Mt = 4;
Mr = 4;
bit_SMsym = log2(M*Mt); % number of bit per sysmbol
Nbits = bit_SMsym*1e4; % Number of bits to be simulated.
hmodem = modem.qammod('M',M, 'SymbolOrder', 'Gray','InputType', 'bit');
hdemodem = modem.qamdemod('M', M,'SymbolOrder','Gray','OutputType','bit');
Eac = (mean(hmodem.Constellation .* conj(hmodem.Constellation)));
SNR = 0 : 2 :24; % signal-to-noise ratio in dB
No= (Eac)*10.^(-SNR/10); % noise variance
L_SNR=length(SNR);
ber= zeros (L_SNR,1);
bit_R=zeros(Nbits, 1);
bit_T = randi([0 1],Nbits,1);
[mod_T ante]= SpatialMod();
mod_T = mod_T.';
for ii=1:L_SNR
for j = 1 : size(mod_T ,2)
channel = sqrt(.5)*( randn(Mr,Mt,1) + 1i*randn(Mr,Mt,1));
noise = sqrt(.5)*(randn(Mr , 1) + 1i*randn(Mr , 1))* sqrt(No(ii));
p = diag(channel'*channel);
switch mode
case 1
y = channel(:,ante(j))*(mod_T(ante(j) ,j)./sqrt(p(ante(j)))) + noise;
z = (channel'*y)./p.^.5;
case 2
y = channel(:,ante(j)) * mod_T(ante(j) ,j) + noise ;
z = (channel'*y)./p;
end
[UnUsEdVaRiAbLe_To_IgNoRe, ant_est] = max(abs(z));
bi_ant = de2bi(ant_est - 1 , log2(Mt) ,'left-msb');
bi_mod = demodulate(hdemodem, z(ant_est,1) );
bit_R( (j-1)*bit_SMsym+1 : (j-1)*bit_SMsym+bit_SMsym,1) = [bi_ant.' ; bi_mod];
end
[UnUsEdVaRiAbLe_To_IgNoRe,ber(ii,1)] = biterr(bit_T(:,1),bit_R(:));
end
figure(1);
semilogy(SNR,ber(:,1),'color',[0,0.75,0.75],'linestyle','--','LineWidth',2.4);
grid on;
function [signal ant_no]= SpatialMod()
global M Mt hmodem bit_T
Nt = log2(Mt);
Nobit = log2(M);
x1 = reshape(bit_T,Nobit+Nt,[]);
ant_no = bi2de([x1(1:Nt,:)].' , 'left-msb') + 1;
digMod = modulate(hmodem,x1(Nt+1:end,:));
signal = zeros(Mt , length(digMod));
for i = 1 : length(digMod)
signal( ant_no(i) , i) = digMod(i);
end
signal = signal.';

Accepted Answer

Walter Roberson
Walter Roberson on 26 Jan 2017
Get rid of the "clear all"
  2 Comments
Walter Roberson
Walter Roberson on 26 Jan 2017
I loaded in your code, commented out the "clear all", and added in a waitbar. It proceeds as expected. It takes a moment to finish, but not all that long.

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