Error : "Too many input arguments"

Hello, wi type this code in matlab :
f = @(x)mseFunction(x(1),x(2),y,yS);
H=feval(f,xc(1),xc(2));
I get the following error :
Error using @(x)mseFunction(x(1),x(2),y,yS)
Too many input arguments.
Error in projbfgs (line 65)
H=feval(f,xc(1),xc(2));
I do not know where i made the mistake. Thanks!

 Accepted Answer

Star Strider
Star Strider on 3 Jan 2017
Edited: Star Strider on 3 Jan 2017
If I remember correctly from your earlier Question, ‘mseFunction’ only has three arguments. If you want to pass it ‘y’ as well, you have to re-write the function definition to include it:
function MSE = mseFunction(alpha,beta,y,yS)
...REST OF YOUR CODE ...
end
EDIT Please do not use feval here. Just call your function as:
H = f(x);
assuming that ‘y’ and ‘yS’ are already in your workspace.

4 Comments

Hello Star. I have already written this way. Thanks!
I rewrote the mseFunction under this form :
%%Déclaration de la fonction objective qu'on va utiliser
function MSE=mseFunction(alpha,beta,y,yS)
%%Calcul de la moyenne mobile d'ordre 48 pour les 6 jours
%Initialisation du vecteur qui va contenir la moyenne mobile
MMCS=zeros(240,1);
%Calcul de la moyenne mobile
for i=1:240
MMCS(i)=1/48.*((yS(i)/2)+sum(yS(i+1:i+47))+(yS(i+48)/2));
end
%Remplir les 24 premieres et derniéres cases par des zeros
MoyenneMobileCentreeS = padarray(MMCS,24,'both');
%%Calcul des composantes saisonniares
yMS=yS(25:264)./MoyenneMobileCentreeS(25:264);
%Réecrire le vecteur de telle sorte que les 24 premieres et derniére
%valeurs soient des zéros
bS = padarray(yMS,24,'both');
%Ecrire les valeurs du vecteur sous forme d'une matrice avec 48 lignes et 7 colonnes
MS = reshape(bS,[48,6]);
%Remplacer les zeros par des valeurs NaN pour ne pas les introduire dans le
%calcul de la médianne
MS(1:24,1)=NaN;
MS(25:48,6)=NaN;
%Calcul de la médianne de chaque ligne de la matrice
ComposantsSaisonniersS = nanmedian(MS,2);
%%Lissage exponnentiel simple
LES=zeros(288,1);
LES(25)=MoyenneMobileCentreeS(25);
for i=26:264;
LES(i)=alpha.*MoyenneMobileCentreeS(i)+(1-alpha).*LES(i-1);
end
%%Intégration de la composante saisonniére
S=zeros(264,1);
S(1:48,:)=ComposantsSaisonniersS;
for j=49:264;
S(j)=beta.*(yS(j)./LES(j))+(1-beta).*S(j-48);
end
%%Prévision
PREV=zeros(264,1);
PREV(26:264)=S(26:264).*LES(25:263);
PREV2=padarray(PREV(:),24,'post');
%%Calcul de la MSE
MSE = [mean((y(26:264)-PREV2(26:264)).^2),gradIent(alpha,beta,y,yS)'];
My pleasure!
Did my Answer solve your problem?
Hi. The problem is not solved.
I created a version of your function for testing purposes in my function testing ‘.m’ file.
When I ran the following code with it, it ran without error:
function MSE=mseFunction(alpha,beta,y,yS)
MSE = [alpha beta; y yS];
end
xc = [100; 102];
y = 20;
yS = 50;
f = @(x)mseFunction(x(1),x(2),y,yS);
H = f(xc)
H =
100 102
20 50
I cannot reproduce the problem you are getting.

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More Answers (1)

Niels
Niels on 3 Jan 2017
Edited: Niels on 3 Jan 2017
Hi,
yes, your defined f as a function with only 1 inputargument
f = @(x)mseFunction(x(1),x(2),y,yS);
but then you want it to have 2:
H=feval(f,-->xc(1),xc(2)<--);
so your x has to be a vector with length 2...
try
H=feval(f,xc);
or set f to
f = @(x1,x2)mseFunction(x1,x2,y,yS);
and
H=feval(f,xc(1),xc(2));

2 Comments

That won’t work here (see the previous Question Calculate the optimum of a function). The ‘mseFunction’ is an objective function for an optimisation routine, and takes a vector of parameters as an argument.
Hello Niels. I get this error :
Error using mseFunction
Too many input arguments.
Error in @(x1,x2)mseFunction(x1,x2,y,yS)

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