check with all parameter except its own

       3     5     1
       5     2     2
       2     5     2
       5     3     1
       5     1     3
       7     0     2
       6     1     2
       6     0     3
       1     1     7
       1     4     4
       2     1     6
       5     4     0

take 3+5=8--which is not equal to 9

so loop again rotate

take 3+2=5--not equal to 9

same in this manner 5+1=6 not valid 5+5=10 no same as this start from next entry and do process,take allentry as row wise if answer valid than loop stop and do for next element process

[David Barry]

I've read that a couple of times now and still have no idea what you are asking. Can you explain it better?

[Pratik Anandpara]

take element of matrix and sum with next element and check total =10 if not than take next element and again check sum

matrix(1,1)=3
3+5=8

3+1=4
3+5=8
3+2=8
3+2=5
3+2=5
3+2=5
3+2=5......3+7=10 loop stop
print-3 is valid

now matrix(1,2)=5
5+1=6
5+5=10...loop stop
5 is valid

matrix(1,3)=1
1+5=6 
1+2=3
1+2=3
1+2=3...check with all other elements..except its own

[Pratik Anandpara]

@david Barry now got?

[David Barry]

No still don't get it. Please upload a mat file containing your matrices.

[Pratik Anandpara]

mat file is more complicated i take example matrix :

1 2 3
4 5 6
7 8 9

goal is total=10

now take 1+2=3
1+3=4...1 
1+4=5
1+5=6
1+6=7
1+7=8
1+8=9
1+9=10
stop this process now
print...1 is valid after 8 process

now take 2+3=5
2+4=6
2+5=7
2+6=8
2+7=9
2+8=10
print...2 is valid 6 process

3+4=7
3+5=8
3+6=9
3+7=10....3 is valid after 4 process

4+5=9
4+6=10....4 is valid after 2 process

now
5+6=11
5+7=12.......upto 5+4=9
5 is not valid(not take own sum)

6+7=13.6+8=14...6+9=15...6+1=7...6+2=8...6+3=9...6+4=10
6 is valid after 7 process

like this take row wise sequence...random matrix take but process same

[Pratik Anandpara]

@david barry...still?....i will mail you if you stil not get

[Image Analyst]

He might have given up because it's not well explained. So do you want to add every element to every other element, or even all possible other elements, until you find all the combinations that equal some desired integer value?

I have two more questions. (2) How large could this matrix be? and (3) have you tried a intuitive and simple brute force "for" loop?

[Pratik Anandpara]

use any loop ..matrix is mostly n*3 ..i tried force also but not set there

[Image Analyst]

Let's see your brute force for loop attempt.

[David Barry]

Yes I have given up. Poor explanation, no code and no data. I'm out.

[Jan]

I do not understand the explanations also. What do you want to achieve?

Answer 1

[KSSV]

Let A be your matrix.

B=A(:);
N = length(B);
iwant=zeros(N,2);
for i=1:N
    count=0;
    C=setdiff(B,B(i));
    for j = 1:N-1
       count=count+1;
       if B(i)+C(j)==10
           iwant(i,:)=[B(i) count];
           break
       end 
    end
end

[KSSV]

count is not required ...You can directly take j in place of count.