How can i flip specific bit of an binary array.

suppose i have a=[1 0 1] and i want to flip the 2nd position bit then i can do by a([2])=~a([2]). but let if a = [1 0 1; 0 1 1; 1 0 0; 1 0 1](large matrix of binary numbers] then , how can a specific bit can be flipped.

Answer 1

[James Tursa]

E.g., the bit in the (2,3) position:

a(2,3) = ~a(2,3);

[Anmol Shah]

I am trying this code but getting the error

"Conversion to char from logical is not possible."

I'm using the below commands

z=(dec2bin(20))

z(1,1) = ~z(1,1);

[James Tursa]

The ~ operator is appropriate for logical or numeric variables. For char variables that you know to contain only '0' and '1' characters, you could just do the following:

z(1,1) = '0'+'1'-z(1,1);

The expression on the rhs is double, but will be converted back into char as a result of the indexed assignment on the lhs. If you are not doing an indexed assignment, you may need to wrap the expression in the char( ) function:

char('0'+'1'-z(1,1))