taking monthly correlation values

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The following example code can be used to calculate the correlation between a data set:
clear all
FieldName = {'loc1','loc2','loc3','loc4'};
data = rand(8760,4);
R = corrcoef(data,'rows','pairwise');
R_Values= [FieldName(nchoosek(1:size(R,1),2)) num2cell(nonzeros(tril(R,-1)))];
Here, 8760 refers to one year worth of data, where a measurement is taken every hour. I'm trying to alter this code to calculate the correlation for every month of the year so that I am left with 12 correlation values for each pair vectors. What would be the best way of doing this?
  2 Comments
Kevin Holst
Kevin Holst on 6 Mar 2012
When you say every month of the year, does it have to correspond to the start of calandar months, or can you just take your data and take 12 evenly spaced samples?
Richard
Richard on 6 Mar 2012
The start of the data i.e. the first row corresponds to the first day of the year, so from then on I can just just take 12 evenly spaced samples. So from the first row, every 24 rows would refer to one day... and so on.

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Accepted Answer

Andrei Bobrov
Andrei Bobrov on 6 Mar 2012
dnew = mat2cell(data,eomday(2011, (1:12))*24,size(data,2));
k = cellfun(@(x)num2cell(nonzeros(tril(corrcoef(x),-1))),dnew','un',0);
out = [FieldName(nchoosek(1:numel(FieldName),2)) [k{:}]];

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