How to pass structure data into parfor loop
Show older comments
Hi all,
I have a simple parfor test code like this:
inpt.a1 = rand(100);
inpt.a2 = rand(100);
parfor i = 1:10000
inpt_pass = inpt;
otpt = sin(inpt_pass.a1);
end
I wrote inpt_pass in order to pass the structure inpt into the parfor loop. However, if inpt is a very large structure, passing it into every parfor loop would be cumbersome, and cost loads of storage.
If I do:
inpt.a1 = rand(100);
inpt.a2 = rand(100);
parfor i = 1:10000
inpt_pass = inpt.a1;
otpt = sin(inpt_pass.a1);
end
which only pass part of the structure into parfor loop (ideal), I got the broadcast variable warning.
So how can I do it? Many thanks!
1 Comment
I am in a similar situation but I would like to pass to each worker a different part of the struct -- i.e. the content of a given field and only that content (not the whole struct). Following the example above, I'd like to write something like:
inpt.a1 = rand(100);
inpt.a2 = rand(100);
% ...
inpt.aN = rand(100);
parfor i = 1:N
fieldname = sprintf('a%i',i);
inpt_pass = inpt.(fieldname);
otpt = sin(inpt_pass);
end
Is it true that the entire struct is not passed into the parfor loop in that case, thus saving memory? If the answer is negative, what alternatives do I have?
Accepted Answer
More Answers (1)
Sean de Wolski
on 23 Nov 2016
Edited: Sean de Wolski
on 23 Nov 2016
0 votes
Use a cell array instead of a structure - they can be easily sliced by index. Or, less preferably, in newer releases turn the structure into a parallel.pool.Constant so that it persists on the workers.
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!