Clear Filters
Clear Filters

How do I calculate the proportion of 1s in Vector I at each time step and how to store this data in a vector?

2 views (last 30 days)
How do I calculate the proportion of 1s(infected) in my vector I at each loop. Is there a way of storing this information? as when I increase my matrix to 100x100 it will be helpful to have the proportion at each loop outputted somewhere which is easy to read.
A=[1,1,0;1,1,1;0,1,1] %Network Matrix
I=[1;0;0] %Vector of Infected at i=0
for i=1:2 %Calculates those infected at i=1 and i=2
I=A*I %Network Matrix times vector at the different times
I>0 %True/False Check: 0=not infected, 1=infected
end
Thank you

Accepted Answer

Massimo Zanetti
Massimo Zanetti on 9 Oct 2016
Edited: Massimo Zanetti on 9 Oct 2016
Given a vector of 1s and 0s, you can divide the number of 1s by the overall number of elements. The nnz function computes the number of non-zero elements in array, so:
I = [1,1,0,1,1,1,0,1,1] ;
n = numel(I);
proportion = nnz(I)/n;

More Answers (0)

Categories

Find more on Operating on Diagonal Matrices in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!