How to find which column consists character 'example' in cell c{1,2}(:,1)

so I have a cell called 'c', I want to know which column the characters 'example' exist in c{1,2}(:,1).... Is there a function that can do this? Or do I need to write my own loop?

What is the syntax for finding character within a cell?

Thanks

Answer 1

[George]

strcmp(c{1,2}(:,1), 'example')

will return a logical array. You may need to surround 'example' with cellstr(), I can't recall.

Answer 2

[dpb]

So many possibilities of how things can be stored in cell arrays likely need a small example to see just what your arrangement actually is, but the following idiom is often useful...

s(~cellfun(@isempty,strfind(s,STRING)))

where s is the array and STRING is the target value looking for. The above returns those elements found;

ix=~cellfun(@isempty,strfind(s,STRING));

the indices into the cell array s the locations found containing STRING.

ADDENDUM

Is the following something like what you have, maybe?

>> c{2,1}='This is a string containing ''REPLACE'' within it'
c = 
  []
  'This is a string containing 'REPLACE' within it'
>> cellfun(@(s) strfind(s,'REPLACE'),c,'uniform',0)
ans = 
  []
  [30]
>>