Replace a missing string in a table
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I want to replace all missing strings in a table with a string of my choice, say 'unknown'. I use R2016a (without an upgrade option), so functions like fillmissing are not available to me, in case they could be of help. Eg:
dblVar = [NaN; 3; 7; 9];
cellstrVar = {'one'; 'three'; ''; 'nine'};
categoryVar = categorical({''; 'red'; 'yellow'; 'blue'});
A = table(dblVar, cellstrVar, categoryVar)
A =
dblVar cellstrVar categoryVar
______ __________ ___________
NaN 'one' <undefined>
3 'three' red
7 '' yellow
9 'nine' blue
I would like to end up with this:
A =
dblVar cellstrVar categoryVar
______ __________ ___________
NaN 'one' unknown
3 'three' red
7 'unknown' yellow
9 'nine' blue
Note I also replaced the categorical '<undefined>' as well, if you can please include in your answer.
Is there a way to do this without changing A's structure, eg from table to cell, in the process? The reason I want to avoid the transformation is my table is large, and transformation may cause memory issues.
Edit to add: the location of the missing string value has to be identified as well, there may be several such columns in the table.
Many thanks.
Accepted Answer
More Answers (1)
Peter Perkins
on 3 Oct 2016
George's loop seems fine to me although you could tweak it a bit as
for name = varNames
var = A.name;
if iscellstr(var)
var(strcmp(var,'')) = {'unknown'};
elseif iscategorical(A.(name))
var(isundefined(var) = 'unknown';
end
A.Name = var;
end
If you're willing to write a couple of small functions, you can do this:
theCellStrs = varfun(@iscellstr,A);
A(:,theCellStrs) = varfun(@replaceEmptyString,A(:,theCellStrs));
function c = replaceEmptyString(c)
c(strcmp(c,'') = {'Unknown'};
(and similarly for categorical) but varfun uses a loop underneath.
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