Nothing on my plot is showing up, anyone know why?

 figure(1);
 clf;

 x = [linspace(50,100,1000) linspace(0,50,1000)];
 z = -x(1).*x(2).*exp(-(x(1)^2 + x(2)^2)./3);
 plot(x,z,'c-');

Answer 1

[Chad Greene]

Something's there, but it's a straight line of zeros because exp(-(x(1)^2 + x(2)^2)./3) equals zero and cyan is difficult to see.

[Luke Radcliff]

well not always say if i do like

x= [1 1] or x = [3 5]

I get values but they are negative. I guess I should just set the domain so i can see the negatives, how do i do that

[Luke Radcliff]

the equation also isn't giving me a vector of answers just 1.

Answer 2

[Walter Roberson]

You define your x as the row concatenation of two linspace() . You extract two values from that linspace and you plot. And the portion you plot is numerically zeros.

 [x1,x2] = ndgrid(linspace(-10,10,1000), linspace(-10,10,1000));
 z = -x1.*x2.*exp(-(x1.^2 + x2.^2)./3);
 surf(x1, x2, z, 'edgecolor', 'none');

[Luke Radcliff]

not quite sure what this is, because im pretty new to matlab. The graph is supposed to be 2d, from this equation in the pic I attached, I was probably too broad about my problem.

[Walter Roberson]

You have two independent variables, x and y, and one depending variable, z. You need 3 dimensions to plot the shape it makes. You could, though, instead produce a 2D image that is color coded:

imagesc(z)

[Luke Radcliff]

3 variables, yea why did I think i could... been a long day, don't even have to graph it I read the question wrong. Thanks for your help though.