adding index to matrix rows
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I have a matrix like this
1 0
0 2
2 1
0 3
3 2
2 0
4 1
1 6
6 4
6 1
I would like to have the following matrix, please help me if you have the answer.
0: 1 0
1: 0 2
2: 2 1
3: 0 3
4: 3 2
5: 2 0
6: 4 1
7: 1 6
8: 6 4
9: 6 1
0 Comments
Accepted Answer
Guillaume
on 27 May 2016
Edited: Stephen23
on 27 May 2016
Please use the code format button {}Code rather than putting spaces between each line.
A matrix can only contain numbers, colons are not allowed. If it's only for display that you want that, there's no simple way to force matlab to display matrices like this.
Possibly, you can convert the matrix into a table and assign names to the rows:
m = [1 0;0 2; 2 1; 0 3; 3 2; 2 0; 4 1];
t = array2table(m, 'RowNames', sprintfc('%d:', 1:size(m, 1)), 'VariableNames', sprintfc('col%d', 1:size(m, 2)))
Otherwise, you'll have to write your own display function which is far from trivial if you want it to play nicely with format.
6 Comments
Guillaume
on 27 May 2016
Well simply modify the relevant fprintf:
fprintf('%d:', row - 1);
More Answers (1)
Renato Agurto
on 27 May 2016
Edited: Renato Agurto
on 27 May 2016
Is this what you want? Or what do you mean with ':' in a matrix?
A = [1 0;
0 2;
2 1;
0 3;
3 2;
2 0;
4 1;
1 6;
6 4;
6 1];
B = [(0:size(A,1)-1)' A];
2 Comments
Allison Chua
on 6 Oct 2020
@Renato Agurto - thank you SO much!!! I'm so terrible at Matlab syntax, and this was exactly what I needed.
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