Creating Matrix with nested loop values

Hello, I am looking for a solution with my problem storing the output of my nested loop into a matrix. The code works perfectly fine and gives me a row for every looped index. For example :
xm =
2 56 31
xm =
2 57 24.667
What i want:
All rows together in one Matrix. hours,minutes,seconds are double values format %f
zeit = [hours minutes seconds ];
houra=1;
minutea=1;
houre=1;
minutee=1;
for k=2:3
for n=1:60
houra=k-1;
minutea=n-1;
houre=k;
minutee=n;
x=(zeit(zeit(:,1)>=houra & zeit(:,1)<houre & zeit(:,2)>=minutea & zeit(:,2)<minutee ,:));
xm=mean(x);
end
end
I hope you can help me.

 Accepted Answer

[a,~,c] = unique(zeit(:,1:2),'rows');
xm = [a, accumarray(c,zeit(:,3),[],@mean)];

3 Comments

Hello, thanks for your help, it works fine for just the (:,3) value but i have a total of 12 i want to mean and store in the matrix.
Hi Peter! For zeit with size [m x 12]:
[m,n] = size(zeit);
[a,~,c] = unique(zeit(:,1:2),'rows');
[x,y] = ndgrid(c,1:n-2);
A = zeit(:,3:end);
xm = [a, accumarray([x(:),y(:)],A(:),[],@mean)];
WOW thank you very much!

Sign in to comment.

More Answers (1)

Jan
Jan on 14 Apr 2016
Edited: Jan on 14 Apr 2016
zeit = ???
size1 = 2 * 60;
xm = zeros(size1, 3);
ixm = 0;
for k = 2:3
hMatch = (zeit(zeit(:,1) >= ha & zeit(:,1) < he);
for n = 1:60
ha = k-1;
ma = n-1;
he = k;
me = n;
mMatch = (hMatch & zeit(:,2) >= ma & zeit(:,2) < me);
ixm = ixm + 1;
xm(ixm, :) = mean(zeit(hMatch & mMatch, :));
end
end

1 Comment

Thank you for your help very much, but i doesn t work for me.

Sign in to comment.

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!