problem with togglebutton callback

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alex
alex on 7 Mar 2016
Commented: alex on 7 Mar 2016
This is the code of the two togglebuttons which i created in guide. when i press the first togglebutton i activate the second one too, however the code in the first togglebutton isn't executed.
After i call the
togglebutton2_Callback(handles.togglebutton2, eventdata, handles)
nothing appears at the edit1 as i expect.
The code in button2 runs normally and i see the results at edit2.
function togglebutton1_Callback(hObject, eventdata, handles)
ispushed=get(hObject,'Value');
if ispushed
set(hObject, 'String', 'STOP');
else
set(hObject, 'String', 'START');
end
set(handles.togglebutton2, 'Value', 1);
togglebutton2_Callback(handles.togglebutton2, eventdata, handles)
x=0;
set(handles.edit1, 'String', x);
function togglebutton2_Callback(hObject, eventdata, handles)
tic;
while get(hObject,'Value')
b=toc;
set(handles.edit2, 'String', floor(b));
drawnow
end
What am i doing wrong?
And one more question, how do i stop the execution of the code in button2 by pressing the button1?
  1 Comment
Adam
Adam on 7 Mar 2016
As it stands the loop in togglebutton2_callback is infinite which is why your code in togglebutton1_callback never completes and edit1 is never updated.
Pressing togglebutton1 again will simply queue the instruction until togglebutton2 has finished executing which it never will.

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Accepted Answer

Geoff Hayes
Geoff Hayes on 7 Mar 2016
alex - look closely at the code in your togglebutton1 callback
set(handles.togglebutton2, 'Value', 1);
togglebutton2_Callback(handles.togglebutton2, eventdata, handles)
x=0;
set(handles.edit1, 'String', x);
You set the string for the button and then call the callback for togglebutton2 which includes a while loop. And so long as the condition of the while loop is true, we will never exit the togglebutton2_Callback function and control will never return to togglebutton1_Callback...which means that x never gets initialized and the edit1 control never gets updated. So you probably want to do this before calling the other function.
I don't understand the purpose of the second toggle button. Why is it necessary if the first toggle button starts the counter? Would the user ever push the second toggle button callback? If absolutely necessary, then you could modify your code to be as follows
function togglebutton1_Callback(hObject, eventdata, handles)
ispushed=get(hObject,'Value');
if ispushed
set(hObject, 'String', 'STOP');
x=0;
set(handles.edit1, 'String', x);
set(handles.togglebutton2, 'Value', 1);
togglebutton2_Callback(handles.togglebutton2, eventdata, handles)
else
set(hObject, 'String', 'START');
set(handles.togglebutton2,'Value',0);
end
The above is similar to what you have shown. Note that in the body of the else we set the Value property to zero for the second toggle button so that we exit from the while loop in its callback.
You may want to reconsider some of this code. Ask yourself if the second toggle button is necessary and how you may just use the first one to control the updates to the edit boxes.
  5 Comments
Geoff Hayes
Geoff Hayes on 7 Mar 2016
Alex - in your above pseudocode, you don't mention the second toggle button. So how is that used?
And rather than using a while loop, I would do something similar to the following pseudocode in the togglebutton1 callback
if togglebutton1 is pressed
start periodic timer to update chronometer
set mouse click count to zero
else
stop periodic timer
end
And then, I would create a ButtonDownFcn callback for my GUI (figure) that would be
function figure1_ButtonDownFcn(hObject, eventdata, handles)
if get(handles.togglebutton1,'Value')
numMouseClicks = str2num(char(get(handles.edit1,'String')));
if isempty(numMouseClicks)
numMouseClicks = 0;
end
numMouseClicks = numMouseClicks + 1;
set(handles.edit1,'String',num2str(numMouseClicks));
end
The above callback would be responsible for updating the edit1 text control so long as the togglebutton1 has been pressed.
As an aside, you may wish to use static text controls instead of the edit text control (unless you expect the user to update them?).
For the timer, see Create object to schedule execution of MATLAB commands for details on how to start a periodic timer with a callback that will update the other text control.
alex
alex on 7 Mar 2016
Thank you Mr Geoff, the periodic timer is what i need, i didn't know its excistance. Hace a nice day!

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More Answers (1)

Adam
Adam on 7 Mar 2016
function togglebutton1_Callback(hObject, eventdata, handles)
ispushed=get(hObject,'Value');
if ispushed
set(hObject, 'String', 'STOP');
else
set(hObject, 'String', 'START');
end
set(handles.togglebutton2, 'Value', 1);
if ispushed
togglebutton2_Callback(handles.togglebutton2, eventdata, handles)
x=0;
set(handles.edit1, 'String', x);
end
function togglebutton2_Callback(hObject, eventdata, handles)
tic;
while get(hObject,'Value') && get( handles.togglebutton1, 'Value' )
b=toc;
set(handles.edit2, 'String', floor(b));
drawnow
end
should work.
  1 Comment
alex
alex on 7 Mar 2016
i guess i wasn't clear enough about what i'm trying to do.
Adam, whith your code when the code finishes at the togglebutton2 THEN the code in togglebutton1 continues.
What i want is that both codes in both buttons run simultaneously. I don't want to wait when i call the togglebutton2_Callback until the code in button2 finish, but i want to continue immidiately in the next line.

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