NaN when calculating average
4 views (last 30 days)
Show older comments
I read data from a .xls file using xlsread. There are some 3000 rows with price data, all in number format in excel. I further try to calculate the average of previous 10 days for every day using mean2(prices(i-10,1):prices(i,1)). I do this for last 2990 rows. surprisingly a lot of these throw NaN. I have also run a check "isnan" on each element in prices and none of them tests positive. also stumbled on something:
isnumeric(NaN)
ans =
1
how is this working??
0 Comments
Accepted Answer
David Young
on 22 Jan 2012
Although a NaN is not a number, it is of class double, and so it is numeric. If a NaN was not numeric, it could not be held in a matrix with other numbers.
Your problem is that prices(i-10,1):prices(i,1) may be empty, so mean2 returns NaN. In fact, that expression doesn't look likely to be correct. I suspect you intended to use mean2(prices(i-10:i, 1)).
0 Comments
More Answers (2)
Andrew Newell
on 22 Jan 2012
You could use nanmean to ignore the NaN's while calculating means:
prices = rand(20,20);
n = size(prices,1); m = size(prices,2); window=10;
runningMean = zeros(n-window,m);
for ii=1:n-window
runningMean(ii,:) = nanmean(runningMean(ii:ii+window-1,:));
end
Note that I am interpreting your statement of "previous 10 days" as the ten days before the current day. Your version is actually averaging 11 days.
6 Comments
Atakan
on 22 Jan 2012
This is my code:
function [randnormal]=atakan(a,b,m)
randnormal=[];
count=1;
while (count<=m)
R = normrnd(a,b);
u1=unifrnd(0,1);
u2=unifrnd(0,1);
y=tan(pi*(u1-1/2));
if (u2<=((sqrt(exp(1))/2)*(1+y^2)*(exp(1)^(-y^2/2))))
randnormal=[R;y];
end
count=count+1;
end
Atakan
on 22 Jan 2012
Hi; I want to ask a question to the main page. But it gives an error such that "we are sorry but something went wrong". What can I do?
3 Comments
Atakan
on 22 Jan 2012
I have tried many many times. But there is still a problem. If I send the question to you, can you ask the question for me? Because this is very important for me. thanks...
See Also
Categories
Find more on Logical in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!