how can i find same values in an array?

139 views (last 30 days)
I have an array a, where
a=[303.1093
94.5581
86.6591
108.1389
303.1093
107.4338
138.6919
106.8294
108.1389
149.3491
187.8940
125.0922
96.7580
303.1093
75.9192
96.2085
118.8788
303.1093
303.1093
303.1093]
then i wanna do
b=round(a);
In b I want to find the positions who are having same values and I want to mark those value as 1 and others 0.
please help me.
Thank you
-- Suchi
  2 Comments
Meghana Dinesh
Meghana Dinesh on 5 Feb 2016
Edited: Meghana Dinesh on 5 Feb 2016
How much "similar"? Or do you mean "same"?
suchismita
suchismita on 5 Feb 2016
Edited: suchismita on 5 Feb 2016
yes same values

Sign in to comment.

Accepted Answer

Star Strider
Star Strider on 5 Feb 2016
Edited: Star Strider on 5 Feb 2016
The unique function will obviously provide the information you want, but ‘the positions who are having similar values’ is less clear. I believe the au (unique values in ‘a’) and ‘ic’ values (the indices in ‘a’ that correspond to them) is what you want:
[au,ia,ic] = unique(round(a),'stable')
EDIT —
‘I wanna mark those same values as 1 and others 0’
I believe this does what you want:
[au,ia] = unique(round(a),'stable');
Same = ones(size(a));
Same(ia) = 0;
Result = [a Same]
Result =
303.11 0
94.558 0
86.659 0
108.14 0
303.11 1
107.43 0
138.69 0
106.83 1
108.14 1
149.35 0
187.89 0
125.09 0
96.758 0
303.11 1
75.919 0
96.209 0
118.88 0
303.11 1
303.11 1
303.11 1
-
  4 Comments
Star Strider
Star Strider on 5 Feb 2016
I wasn’t certain what you wanted. I thought you only wanted to flag the repeated values, other than the first occurrence. Since this now seems to be resolved, I’ll not pursue it further.
Stephen23
Stephen23 on 5 Feb 2016
Good point about the "first occurrence". This did not occur to me, and the original question is ambiguous on this point.

Sign in to comment.

More Answers (3)

Stephen23
Stephen23 on 5 Feb 2016
This identifies all matching rounded values, unlike the accepted answer:
b = round(a(:));
c = bsxfun(@eq,b,b.');
x = any(tril(c,-1)|triu(c,1),1);
[a(:),+x(:)]
303.1093 1
94.5581 0
86.6591 0
108.1389 1
303.1093 1
107.4338 1
138.6919 0
106.8294 1
108.1389 1
149.3491 0
187.8940 0
125.0922 0
96.7580 0
303.1093 1
75.9192 0
96.2085 0
118.8788 0
303.1093 1
303.1093 1
303.1093 1
  1 Comment
suchismita
suchismita on 6 Feb 2016
i want to accept your answer but i dont how to unlike the already accepted answer?

Sign in to comment.


Bhavini Sarkar
Bhavini Sarkar on 17 Sep 2016
To find the duplicate elements of an array, first you should sort array . After sorting all duplicate elements will aggregate in adjacent positions. Now using a for loop , traverse sorted array and compare adjacent elements. If adjacent elements are equal then you found one duplicate element of array . We can also find duplicate elements of an array in linear time using some extra space.

Azzi Abdelmalek
Azzi Abdelmalek on 5 Feb 2016
[ii,jj,kk]=unique(a,'stable')
  1 Comment
suchismita
suchismita on 5 Feb 2016
I wanna mark those same values as 1 and others 0, how can i do that

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!