How to merge multiple bounding box into one?

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How do I merge multiple bounding on the same object as one bounding box around the object? Below is an example. Thanks

Answers (3)

Walter Roberson
Walter Roberson on 27 Jan 2016
Edited: Image Analyst on 27 Jan 2016
Convert the [x y width height] coordinates to start and end coordinates,
[x y x+width-1 y+height-1]
Now take the minimum of all of the left x over all of the boxes to get the left bound, the maximum over all of the right x to get the right bound, the minimum over the top y to get the lower bound, the maximum over the bottom y to get the upper bound.

Nibir Sarker
Nibir Sarker on 13 Dec 2018
Please Provide me the full code for multiple bounding box converting into one bounding box.In the below figure i want to merge trash and human bounding box together then count the object and detect human and trash together.
sample.jpg
  4 Comments
Mangaraju Palepu
Mangaraju Palepu on 24 May 2021
Edited: Mangaraju Palepu on 24 May 2021
Regardless of merging bounding boxes. The text will be detected when used OCR. I see no text in your image. so it is obvious that function OCR detected no text.
anyways to merge two bounding boxes they should overlap first. Increase the size of bounding boxes, make them overlap and try to merge. change the valuse expansionAmount in your code.
By the way you totally copied the exaple code from matlab. And only use either regionprops or stoke width variation to remove non text region , the code you copied using both. only one method has to opt.
Walter Roberson
Walter Roberson on 25 May 2021
The images were posted by @Nibir Sarker and are probably not the same ones uses by @Saketh Nannaka .

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kalpana k
kalpana k on 24 Nov 2022
Edited: Walter Roberson on 24 Nov 2022
if you are having the binary image as "I7", follow the below code to merge all the regions into common bounding box as below
RegionAll=regionprops(I7,'BoundingBox');
BBall=[];
for jk=1:length(RegionAll)
Box1=RegionAll(jk).BoundingBox;
Box2=[Box1(1) Box1(2) Box1(1)+Box1(3)-1 Box1(2)+Box1(4)-1];
BBall=[BBall ;Box2];
end
mX=min(BBall(:,1));
mY=min(BBall(:,2));
mW=max(BBall(:,3))-mX;
mH=max(BBall(:,4))-mY;
NewBB=[mX mY mW mH];
  1 Comment
Walter Roberson
Walter Roberson on 24 Nov 2022
No loop needed
RegionAll=regionprops(I7,'BoundingBox');
AllBoxes = vertcat(RegionAll.BoundingBox);
xy = [AllBoxes(:,1:2), AllBoxes(:,1:2) + AllBoxes(:,3:4));
startX = min(xy(:,1));
startY = min(xy(:,2));
endX = max(xy(:,3));
endY = max(xy(:,4));
BB = [startX, startY, endX - startX, endY - startY];

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