help writing a script that tells the day of the week

I need help writing a code that tells me the day of the week as well as the number of the day relative to the year. Ex: input form month/day/year: xx/xx/xxxx output should say something like: The date 08/31/2011 is the 243 day of the year and is a wednesday.

I have tried so many different things from Mathworks with no luck.

[John D'Errico]

disp('Today is Monday")

Correct at least once a week. Oh. did you want it to get the day right, all the time?

[bachir]

I've got it from Star Strider

Answer 1

[Star Strider]

One way (not using datetime, since not everyone may have it):

InpStr = '08/31/2011';
YrStart = datenum(InpStr(end-3:end), 'yyyy');
dtnm = datenum(InpStr, 'mm/dd/yyyy');
[DayOfWkNum,DayOfWkStr] = weekday(dtnm,'long');
fprintf(1, '\n\tThe date %s is the %d day of the year and is a %s\n', InpStr, dtnm-YrStart+1, DayOfWkStr)

  The date 08/31/2011 is the 243 day of the year and is a Wednesday

[bachir]

Star Strider, You the man! or woman...! I modified it a little to fit my style but thanks a lot

[Star Strider]

My pleasure, and quite definitely male!

Have fun!

Answer 2

[Peter Perkins]

... and another way, using datetime (if you have R2014b or later):

>> d = datetime('08/31/2011','InputFormat','MM/dd/yyyy')
d = 
   31-Aug-2011
>> day(d,'dayofyear')
ans =
   243
>> day(d,'name')
ans = 
    'Wednesday'

Answer 3

[Stephen23]

The grammar pedants amongst us may appreciate my FEX submission datestr8601, which provides a day-of-the-year string with the correct ordinal suffix:

>> X = [2011,08,31];
>> [A,B,C] = datestr8601(X,'*ymd','nnn','DDDD')
A =
2011-08-31
B =
243rd
C =
Wednesday
>> sprintf('The date %s is the %s day of the year, and is a %s.',A,B,C)
ans =
The date 2011-08-31 is the 243rd day of the year, and is a Wednesday.