selecting an image from folder
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I have 30 images in a folder,I have to select only21st image from it,please help,i tried this code but only first image is shown
I have 30 images in folder named photos
path='D:\photos\';
files=dir(strcat(path,'*.jpg'))
for k=1:numel(files(21))%numel(files)
file_name=files(k).name;
image_name=strcat(path,file_name);
I=imread(image_name);
figure,imshow(I)
end
2 Comments
kash
on 29 Dec 2011
Image Analyst
on 29 Dec 2011
Look up the mod() function to take every 5th one.
Accepted Answer
More Answers (1)
Chandra Kurniawan
on 22 Dec 2011
Then you just need to pass your feature vector 1x80 and
feature vector of query image in
suppose that dataset1 is feature vector 1x80
dataset2 is feature vector of query image
function D = DistEuclidian(dataset1, dataset2)
[m1 n1] = size(dataset1);
[m2 n2] = size(dataset2);
D = zeros(m1, m2);
for i = 1 : m1
for j = 1 : m2
D(i, j) = sqrt((dataset1(i, 1) - dataset2(j, 1)) ^ 2 + ...
(dataset1(i, 2) - dataset2(j, 2)) ^ 2);
end
end
And you'll get the Distance matrix.
Then make a limit. If all values in Distance matrix lower than your limit,
We can say that your query image is match with feature vector 1x80
7 Comments
FIR
on 22 Dec 2011
But Chandra How to retrieve the image finally
kash
on 22 Dec 2011
kash
on 22 Dec 2011
Chandra Kurniawan
on 22 Dec 2011
Please send me the MAT file of 'feature vector 1x80'
and tell me what are feature vector of query image.
It's hard if I only imagine about that.
kash
on 22 Dec 2011
kash
on 28 Dec 2011
Image Analyst
on 28 Dec 2011
Did you try
% Multiply by 2 and divide by 2, for some weird reason.
newVector = (2*data80) / (2*data80); % Not sure of the point.
% Get running average.
output = conv(newVector, ones(1,8)/8, 'valid');
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