Normalized cross-correlation function
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    Manolis Michailidis
      
 on 18 Sep 2015
  
    
    
    
    
    Commented: devi sowjanya
 on 6 Mar 2021
            Hello, i am trying to write a normilized cross-correlation method function , but i can't complete it. Here are the details of the formula :

My code is
x=rand(1,1000);
N=length(x); %// length of signal
n1=128;  %// length of window 
xf=framing(x,n1,n1/2,rectwin(n1)); %this function frames the signal i will get xf(128,14)
win_num=size(xf,2);
for col=1:win_num
   for m=1:n1+1 
      for n=1:n1-m
         ccor(m,col)=sum(xf(n+m,col)*(xf(n,col)))/ sqrt(sum(xf(n)^2)*sum(xf(n+m)^2) );
      end
   end
end
Note that i want to see the correlation values betwen -1 and 1 like in the figure but instead i get

.
1 Comment
Accepted Answer
  Kirby Fears
      
 on 21 Sep 2015
        
      Edited: Kirby Fears
      
 on 21 Sep 2015
  
      Hi Manolis,
To directly replicate what the equations say (shifting indices with +1), the calculation would look more like this:
x=rand(1,1000);
N=length(x); %// length of signal
n1=128;  %// length of window
xf=framing(x,n1,n1/2,rectwin(n1)); %this function frames the signal i will get xf(128,14)
win_num=size(xf,2);
% M0=???
ccor=NaN(M0+1,win_num);
for col=1:win_num
    for m=1:M0+1,
        [term1,term2,term3]=deal(0);
        for n=1:N-m,
            term1=term1+xf(n,col)*xf(n+m,col);
            term2=term2+xf(n,col)^2;
            term3=term3+xf(n+m,col)^2;
        end
        ccor(m,col)=term1/sqrt(term2*term3);        
    end
end
You would just need to explicitly specify M0. This calculation can be simplified as follows:
x=rand(1,1000);
N=length(x); %// length of signal
n1=128;  %// length of window
xf=framing(x,n1,n1/2,rectwin(n1)); %this function frames the signal i will get xf(128,14)
win_num=size(xf,2);
% M0=???
ccor=NaN(M0+1,win_num);
for col=1:win_num
    for m=1:M0+1,
        term1=sum(xf(1:N-m,col).*xf(1+m:N,col));
        term2=sum(xf(1:N-m,col).^2);
        term3=sum(xf(1+m:N,col).^2);
        ccor(m,col)=term1/sqrt(term2*term3);        
    end
end
I don't have the toolbox required to run this code, so it may have bugs. Hope this helps.
More Answers (2)
  Kirby Fears
      
 on 18 Sep 2015
        
      Edited: Kirby Fears
      
 on 18 Sep 2015
  
      Hi Manolis,
You are looping n and m by starting at 1, but in the formula you posted the sum starts at 0. You will need to correct your calculations to include the 0 terms in the summation. You should also consider pre-allocating "ccor" to save yourself some computational time.
You may have access to the xcorr function which calculates cross correlations. It has several options to control normalization.
Hope this helps.
2 Comments
  Kirby Fears
      
 on 21 Sep 2015
				Indeed the loop variables are only used as indices, so you are correct. My mistake. I assumed the loop variables were also used as numeric values in the summand. I'm writing another answer below.
  Image Analyst
      
      
 on 29 Sep 2015
        Do you have the Image Processing Toolbox? If so, why not just use the built-in function normxcorr2()?
1 Comment
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