How do I post a picture with my question
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How can I add this image?
1 Comment
Walter Roberson
on 10 Jun 2011
See also this partial list of sites you can upload your picture to:
http://www.mathworks.com/matlabcentral/answers/7924-where-can-i-upload-images-and-files-for-use-on-matlab-answers
Accepted Answer
More Answers (4)
Doug Hull
on 21 Jan 2011
2 votes
Daniel Shub
on 17 May 2012
0 votes
If someone posts a question with a link like http://tinypic.com/r/14bib77/6 and I want to edit the question to embed the image I get

and that looks really ugly. Is there anything I can do besides re-uploading the image?
7 Comments
Walter Roberson
on 17 May 2012
Unfortunately no.
Part of the problem is the image size: the Answers site makes no attempt to resize the images to fit the reader's screen.
Jan
on 20 May 2012
Ask the author to create a cropped version of the image.
Walter Roberson
on 21 May 2012
In the case of tinypic, you can right-click on the preview image and copy the URL of the preview.
Daniel Shub
on 21 May 2012
@Jan, I might be being pessimistic, but I think that is a losing battle.
@Walter, but the preview, at least in this case, has the padding also.
Jan
on 21 May 2012
@Daniel: You can download the image, crop it with the IPT or even in pure Matlab, save it a tinypic again and change the link in the original question. Well, of course the OP could do this also.
Finally I write this only to confirm, that this is a losing battle. Sigh.
Walter Roberson
on 21 May 2012
I embedded that _exact_ preview, in a Question a day or so, and had no difficulty with it being off the right hand side.
Daniel Shub
on 22 May 2012
@Walter, you tried to embed the "exact preview" but you didn't. The question is here:
http://www.mathworks.com/matlabcentral/answers/38620-processing-image-with-deconvolution
Basically there are two images: http://tinypic.com/r/2u95qwg/6 and http://tinypic.com/r/14bib77/6 You embedded the 2u95qwg image twice. If I embed that image it works for me also. The 14bib77 image does not work.
Jan
on 21 Sep 2013
0 votes
Now pictures can be uploaded directly in the forum, see: http://www.mathworks.com/matlabcentral/answers/87583#answer_97176Y . A great step to improve the usability of the forum!
Hamad Abdin
on 31 Oct 2020
0 votes
function [root, fx, es, iter] = modsecantmeth(func, xr, es, del, maxit)
% modsecantmeth: root location
% [root, es, iter] = modsecantmeth(func, xr, es, del maxit:
% uses Modified Secant Method to find roots of func
% input:
% func = name of function
% xr = initial guess
% es = desired relative error ( default = 0.0001%)
% del = perturbation fraction (default = 1e-6)
% output
% root = real root
% ea = approximate relative error (%)
% iter = number of iterations
% operational notes
% none.
if nargin < 2, error('at least 2 input arguments required'),end
if nargin < 3 || isempty(es), es = 0.0001;end
if nargin < 4 || isempty(del), del = 1e-6;end
if nargin < 5 || isempty(maxit), maxit = 50;end
iter = 0;
ea = 100;
while (1)
xrold = xr;
xr =xr - del *xr*func(xr)/(func(xr+(del*xr))-func(xr));
iter = iter +1;
if xr~= 0, ea = abs((xr-xrold)/xr)*100;end
data(:,iter) = [iter, xrold, xr, ea];
if ea <= es || iter >= maxit, break, end
end
root = xr; fx = func(xr);
disp('Secant Method Results')
disp('iter, old xr, new xr, |ea|')
disp('data')
2 Comments
Hamad Abdin
on 31 Oct 2020
can you help me to make run.
Rik
on 31 Oct 2020
This is completely unrelated to this question. Read this https://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer
After that, post this as your own question (don't forget to have a proper layout of your post, see this link: https://www.mathworks.com/matlabcentral/answers/help/rtc#rtc_summary )
This answer will be deleted shortly.
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