how to set intlinprog options

how to set intlinprog options to increase options.maxnodes I've tried both

 options=optimoptions('intlinprog')  ;
 options.MaxNodes=10^16;

and

     optimoptions('intlinprog','MaxNodes',10^16);

    intcon= zeros(34,1);

    for i= 1 : 34
       intcon(i,1)=25+i; 
    end

    D = [ DDD ; eye(25), zeros(25,34); -eye(25), zeros(25,34) ] ;

    f= [zeros(25,1) ; g ; -1 ]  ;
    b=[zeros(33,1); [1-0.0001 ] ; ones(25,1); ones(25,1) ] ;

    options=optimoptions('intlinprog')  ;
    options.MaxNodes=10^16;
     optimoptions('intlinprog','MaxNodes',10^16);

    w = intlinprog(-f,intcon,D,b) ;

However, when I run my code the program keeps setting options.maxnodes to 10^8

    Intlinprog stopped because it reached the maximum number of nodes,
    options.MaxNodes = 10000000 (the default value).

Answer 1

[Matt J]

You define "options", but never pass it to intlinprog.

[Standardtrickyness]

Sorry can you elaborate?

[Matt J]

You call intlinprog here,

w = intlinprog(-f,intcon,D,b) ;

with only 4 input arguments -f,intcon,D, and b. Your "options" is not among the inputs. You need to use the 9-argument syntax

w = intlinprog(f,intcon,A,b,Aeq,beq,lb,ub,options)

[Standardtrickyness]

Thanks a lot, also is there a way to set options for intlinprog in the optimization app? Also can you explain what optimoptions('intlinprog','MaxNodes',10^16); does?

[Walter Roberson]

It creates an options structure using typical options for intlinprog and then setting MaxNodes to 10^16 in that structure.

[Alan Weiss]

As the release notes for R2014a state, you cannot use the Optimization app with intlinprog. Sorry.

Alan Weiss

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