surf plot won't happen because i need a matrix?

3 views (last 30 days)
surf plot won't happen because i need a matrix? I've just introduced a new variable to my script and I tried doing it using a nested loop. Only problem is that when I tried to plot a surface graph it says I should be using a matrix - not a scalar or vector. I just added the variable G - which is angle.
iter=1;
for f=50:1000
for G=0:(pi/2)
rho_a=1.2041;
c=343.26;
L=0.1;
a=0.03;
sigma_pf1=10000;
phi_pf1=0.96;
alpha_pf1=1;
k_a=(2*pi*f)/c;
k_pf1=((2*pi*f)/c)*sqrt(alpha_pf1-((1i*sigma_pf1*phi_pf1)/(2*pi*f*rho_a)));
zc_air=rho_a*c;
zc_pf1=((rho_a*c)/phi_pf1)*sqrt(alpha_pf1-((1i*sigma_pf1*phi_pf1)/(2*pi*f*rho_a)));
zs_pf1=(-1i)*((cos(k_pf1*L)*cos(k_a*a)-(zc_pf1/zc_air)*sin(k_pf1*L)*sin(k_a*a))/((1/zc_pf1)*sin(k_pf1*L)*cos(k_a*a)+(1/zc_air)*cos(k_pf1*L)*sin(k_a*a)));
Rs_pf1=((zs_pf1/(rho_a*c))*cos(G)-1)/(1+(zs_pf1/(rho_a*c))*cos(G));
AbsCoef_pf1=1-(real(Rs_pf1))^2;
Rs_pf1rec(iter)=Rs_pf1;
AbsCoef_pf1rec(iter)=AbsCoef_pf1;
zs_pf1rec(iter)=zs_pf1;
iter=iter+1;
end
end
surf(50:1000,0:(pi/2),AbsCoef_pf1rec,'color','g');
set(hleg,'Location','SouthEast');
set(hleg,'FontSize',16);
set(gca,'FontSize',16);
Any help would be great.

Accepted Answer

Sean de Wolski
Sean de Wolski on 12 Dec 2011
That is correct. Use meshgrid to generate index matrices e.g.:
[xx yy] = meshgrid(linspace(-pi,pi,10));
surf(xx,yy,sin(xx)+cos(yy))
What you have above are three vectors (nx1 or 1xn) and it can't generate a surface of a line.
  3 Comments
Sean de Wolski
Sean de Wolski on 12 Dec 2011
[xx yy] = meshgrid(50:1000,linpace(0,pi/2,number_of_values_between_0_and_pi_over2))
Tom
Tom on 8 Jan 2012
Many thanks for your help on this!

Sign in to comment.

More Answers (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!