High Voltage Transformer design
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I have designed a real world HV transformer however my LCR meter is unable to measure the secondary inductance. I am not sure why this is the case however the reading is needed for simscape/passive/electrical/transformers block. Is this even a realistic simulation or is this pushing modern day simulation software too far? I have tried using the Inductance-Turns Ratio Equation. Here but when putting this in the block my output becomes zero. I am able to use the liniar block and get my expected Voltage output of 40Kv. The entire reason for simulation is 1. learn about simulation and transformers better and 2. troubleshoot my transformer as the power is lower than expected and I want to know if the core is saturating. I have attatched my code below for those interested. Perhaps you can look over the code aslso to check if if the formulas I am using are correct and being used with the correct units. This is my first real transformer design ever as I am at that point in my electronics journy. So basically my transfomrer design works but at a lower power that I expected and designed it for and the simulation doen't seem to work. When I say lower power I mean the voltage must be less than it should be other wise I would have higher current and in turn a larger and brighter arc. Also I have no way to measure such high inductance for the secondary L for my simscape block.


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Answers (1)
Dinesh
10 minutes ago
0 votes
Hi Evan,
The inputs must match the actual ZVS operating conditions. A 28 V supply producing approximately 39 V peak at the primary corresponds to about 27.6 Vrms; therefore the model must use a 39 V-amplitude, 50 kHz source not 60 Hz. The 3:3077 turns ratio produces approximately 40 kV peak (28 kVrms), while 40 kVrms would require about 4350 secondary turns. The secondary inductance need not be measured directly: measure primary inductance with the secondary open and calculate (L_s=L_p(N_s/N_p)^2). For saturation analysis, use measured winding resistance and leakage inductance plus the core material B–H/loss data; a 500 Ω secondary load and 2 kΩ primary resistor are not physically representative and will force the simulated output near zero.
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