How to find values in a nested struct with repeating fieldnames?
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Oswin Hulsebos
on 27 Nov 2024 at 10:33
Edited: Oswin Hulsebos
on 29 Nov 2024 at 11:13
I've got a structure, of which I want to extract data. I think a loop in combination with the find function could do the trick, but this seems like an inefficient and error-prone way. Are there any better methods to obtain the same result?
The resulting structure is nested, where the same fieldnames typically repeat on every level. For example:
A = Struct with fields: X, Y, Z
where
Z = Struct with fields: X, Y, Z
My goal is to extract data from fieldname 'Y' when fieldname 'X' returns a specific value. However, this can be on any layer 'Z'. Hence, examples could be:
Solution = A.Z(ii).Y if A.Z(ii).X == searched value
or
Solution = A.Z(ii).Z(jj).Z(kk).Z(ll).Y if A.Z(ii).Z(jj).Z(kk).Z(ll).X == searched value
2 Comments
Accepted Answer
Yash
on 27 Nov 2024 at 11:29
Hey @Oswin Hulsebos
As @Stephen23 also suggested, recursion would be a good way to do this. Have a look at the example below:
% A is top layer and zVal is under A.Z
zVal = struct('X',2,'Y',4,'Z',struct([]));
A = struct('X',1,'Y',2,'Z',zVal);
% function call
getYIfXisVal(A,2)
% Function for recursion
function yVal = getYIfXisVal(st,val)
if(st.X==val)
yVal = st.Y;
else
yVal = getYIfXisVal(st.Z,val);
end
end
I hope this helps!
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More Answers (1)
Matt J
on 27 Nov 2024 at 11:29
Edited: Matt J
on 27 Nov 2024 at 11:30
I think a loop in combination with the find function could do the trick, but this seems like an inefficient and error-prone way.
I don't know why you think the find() function would be used here. At most, you would need logical indexing.
As for loops, there is no efficient alternative to looping when dealing with structs and cells. Vectorization is only a thing that applies to numeric arrays,.
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