Read and process a Fortran90 binary file
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Hi,
I have a Fortran90 code where a variable called 'stream' is defined such that it stores certain variable every nstep:
open(19,file='stream',form='UNFORMATTED',position='append')
if(mod(NSTEP,100).eq.0)then
write(19)NSTEP,U,W,zeta
endif
How can I properly read the file in Matlab for postprocessing?
FYI, the fortran code is built with double precision.
Thank you
3 Comments
Walter Roberson
ungefär 18 timmar ago
The FORTRAN runtime system embeds the record boundaries in the data by inserting an INTEGER*4 byte count at the beginning and end of each unformatted sequential record during an unformatted sequential WRITE. The trailing byte count enables BACKSPACE to operate on records.
Answers (1)
Les Beckham
ungefär 19 timmar ago
Edited: Les Beckham
ungefär 19 timmar ago
It would help to have a sample file to experiment with.
Nevertheless, assuming that the write call that you have shown is the only thing that writes to this file in your Fortran code, I would suggest something like this using fread and reshape:
fid = fopen('your_file_name.ext', 'rb');
A = fread(fid);
data = reshape(A, 4, numel(A)/4)';
nstep = A(:,1);
U = A(:,2);
W = A(:,3);
zeta = A(:,4);
Note that you might run into endian-ness issues if your Fortran code runs on a different architecture than your Matlab is running on. See the documentation for the machinefmt option to fread if necessary.
4 Comments
Les Beckham
38 minuter ago
Thanks for adding the example.
Can you clarify what you mean by this?
NSTEP is an integer = 2000
Especially the "= 2000" part. Is that just an example of a possible value? What is the size of this integer (number of bits)?
Also, are U, W, and zeta double precision (64 bit) floating point 2-d arrays with the given size?
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