how to mirror data and then plot it?

This question was flagged by dpb
  • Flagged as Duplicate by dpb on 8 Aug 2024.

    < https://in.mathworks.com/matlabcentral/answers/2143774-how-to-mirror-plots>

x =0:1:15;
y = tan(x);
plot(x,y)
i hv to mirror data and then plot also .how to do it

9 Comments

Aniket
Aniket on 8 Aug 2024
Edited: Aniket on 8 Aug 2024
Hi @ramya, Can you please clarify what do you mean by mirroring data. Is it like you want 15..14..13...to.1 ? OR -1, -2, ...-15 ? Basically wrt what axis you want to mirror ?
when i plot the results it plot should be symmetry and data also symmetry
So I understand that you want to mirror along the middle.
Thus
x = 0:1:15;
y = tan(x);
x_new = x;
x_mirrored = fliplr(x_new);
and
y_new = tan(x_mirrored);
Thus the plot obtained will be
figure;
plot(x_new, y_new, 'b', 'DisplayName', 'Symmetric Data');
legend;
xlabel('x');
ylabel('tan(x)');
title('Symmetric Data Plot');
Let me know if this is what was desired.
sir i hv to mirror it from center for example
a= [1 2 3 4 5 6 7 8 9 10] ;
b=[0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.2 0.3] ;
so keeping as threshold to center values
my data will be something
b=[0.2 0.3 0.4 0.5 0.6 0.5 0.4 0.3 0.2]
and then when i plot for b wrt a i get symmetry plots
Something like this ?
ramya
ramya on 8 Aug 2024
Edited: ramya on 8 Aug 2024
the image u showed above is exactly same plots i m looking for plz see the thread for data i m trying
a= [1 2 3 4 5 6 7 8 9 10] ;
b=[0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.2 0.3] ;
ix=fix(numel(a)/2);
c=[b(1:ix) fliplr(b(1:ix))];
plot(a,c)
The above keeps the same number of elements as the original; to do your precise example reduces the number of points by one for an even number...your choice as to which would be the intent/need.
You still haven't precisely defined "symmetry about what?" for the original -- about the minimum, perhaps? That kind of thing may be very dependent upon just what the real application is, not just specifically for the one given example.
But a clear and unambiguous definition of just what "symmetrical" means to you is mandatory...
thank u its similiar i m trying for this particular file pleae follow this thread data is present in this thread
In that case, don't start a new and seemingly unrelated thread...what's wrong with the Answer @Cris LaPierre provided you there? Why don't you amplify in depth what "symmetry" is supposed to mean for the given data which look anything but as given?
It's not possible to answer a question when the specifications for the solution definition aren't clear...you may have a clear understanding of what you mean, but apparently nobody else here does...
I'm flagging this as duplicated to keep the conversation in one place and as a courtesy to those who responded there with best efforts...

Answers (0)

This question is locked.

Categories

Find more on Programming in Help Center and File Exchange

Products

Release

R2021b

Tags

Asked:

on 8 Aug 2024

Locked:

on 8 Aug 2024

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!