difference between 2 values in a vector

Hello Community.
Asking for your help again to find a solution.....
I have a vector with several data points, I'd like to get the difference between each value that is not equal to CERO.
I'm using "diff" command however this includes the difference betwee values that are equal to CERO, here is an example.
x = [0.2 0.0 0.0 0.0 0.25 0.0 0.0 0.0 0.3 0.0 0.0 0.4 0.0 0.0 0.0 0.1 0.0 0.0 0.0 0.35 ]
I tried this : b = diff(x)
b = -0.20 0.0 0.0 0.25 -0.25 0.0 0.0 0.30 -0.30 0.0 0.40 -0.40 0.0 0.0 0.10 -0.10 0.0 0.0 0.35
it gives me the difference between each data point
What I'm trying to get is the difference between each point that is not equal to cero like this:
b = 0.0 0.0 0.0 0.0 0.05 0.0 0.0 0.0 0.05 0.0 0.0 0.1 0.0 0.0 0.0 -0.3 0.0 0.0 0.0 0.25
I don't want to eliminate the ceros in between if I do so it will change the length of the vector and I need to keep same lenght to compare Vs other signals.
the number of ceros between each data value is not always the same, could be 3 ceros in between but it could be 2, 4, 6.....
as always I thank you in advance, your feedback will be higly appreciated.

 Accepted Answer

Try this —
x = [0.2 0.0 0.0 0.0 0.25 0.0 0.0 0.0 0.3 0.0 0.0 0.4 0.0 0.0 0.0 0.1 0.0 0.0 0.0 0.35 ]
x = 1x20
0.2000 0 0 0 0.2500 0 0 0 0.3000 0 0 0.4000 0 0 0 0.1000 0 0 0 0.3500
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Lv = x ~= 0
Lv = 1x20 logical array
1 0 0 0 1 0 0 0 1 0 0 1 0 0 0 1 0 0 0 1
idx = find(Lv);
dx = diff(x(Lv))
dx = 1x5
0.0500 0.0500 0.1000 -0.3000 0.2500
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b = zeros(size(x));
b(idx(2:end)) = dx
b = 1x20
0 0 0 0 0.0500 0 0 0 0.0500 0 0 0.1000 0 0 0 -0.3000 0 0 0 0.2500
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b(1:10)
ans = 1x10
0 0 0 0 0.0500 0 0 0 0.0500 0
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b(11:20)
ans = 1x10
0 0.1000 0 0 0 -0.3000 0 0 0 0.2500
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.

2 Comments

it worked, thanks a lot for taking time to response and for sharing solution
As always, my pleasure!

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More Answers (1)

x = [0.2 0.0 0.0 0.0 0.25 0.0 0.0 0.0 0.3 0.0 0.0 0.4 0.0 0.0 0.0 0.1 0.0 0.0 0.0 0.35 ];
disp(x)
Columns 1 through 18 0.2000 0 0 0 0.2500 0 0 0 0.3000 0 0 0.4000 0 0 0 0.1000 0 0 Columns 19 through 20 0 0.3500
b = zeros(size(x));
idx = find(x ~= 0);
b(idx(2:end)) = diff(x(idx));
disp(b)
Columns 1 through 18 0 0 0 0 0.0500 0 0 0 0.0500 0 0 0.1000 0 0 0 -0.3000 0 0 Columns 19 through 20 0 0.2500

2 Comments

another solution, thank you for sharing it helps a lot to understand more how matlab works
You're welcome!

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Asked:

on 10 Jun 2024

Commented:

on 10 Jun 2024

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