Hi, I need help with coding for large expressions with integrations as given in the image.

I m kind of new to Matlab with average level expertise. Can anybody pls provide code for these or similar equations and then I modify according to these. I have used the integral function in coding for these but all I get is an empty graph with no trend. and NaN. Your guidance/help will be highly appreciated. Thanks

The PrL (u) is the LoS probability function, which is

and theta is

Another equation is

,, Again the PL(v) is the LoS probability

Answer 1

[UDAYA PEDDIRAJU]

Hi Naveed,

Here's a basic Matlab code snippet that demonstrates a definite integral, similar to what you might use for the provided information:

% Define symbolic variables
syms u v theta PL S1 L eta Vi T fi Ta apa dxa rho;

% Define the integrand (replace with your actual function)
integrand = sin(u)*cos(v); % Placeholder function, replace with your actual expression

% Set integration bounds (adjust as needed)
u_lower = 0.0;
u_upper = pi;
v_lower = 0.0;
v_upper = pi;

% Perform numerical integration
result = double(int(int(integrand, v, v_lower, v_upper), u, u_lower, u_upper));

% Print the integration result
disp('Integration result:')
disp(result)

Explanation:

1. We define symbolic variables (syms) to represent the variables in your equations (theta, PL, etc.).
2. The integrand function represents the expression you want to integrate. Replace the sin(u)*cos(v) placeholder with the actual mathematical expression based on your problem.
3. We set the integration bounds (u_lower, u_upper, v_lower, v_upper) for the definite integrals. Adjust these based on your specific problem.
4. The "int" function performs the double integration. We nest the "int" function calls because we're performing a definite integral over two variables. Refer: https://www.mathworks.com/help/matlab/ref/integral.html
5. The "double" function converts the symbolic result to a numerical value.
6. Finally, we display the integration result.

[NAVEED]

Thank you UDAYA for your answer. This is very helpful. I will do the coding and will get back to you if I face any issue.