Find the first appearance of a number in a row.
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Hi I have a matrix A from which I need to return a vector which contain the index of first occurence of a number say 2030 such that we get the matrix below
A = [0   0   0  2095    3030
 0   2030   2030 2030 2030
 0   0   2095   2055    2065
 2065   2055    2050    2030    2030]
B=[5 2 0 4]
I tried using 
    for i=1:4
        d=A(i,:);
        targetval = 2030;
        num_wanted = 2030;
        xx=(find(d==targetval, num_wanted, 'first'))
    end
which apparently does the job (inefficiently) , but I am confused on how to store the indices in a vector and if the value (2030) is not there in a row - then return 0.
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Accepted Answer
  Voss
      
      
 on 28 Sep 2023
        
      Edited: Voss
      
      
 on 28 Sep 2023
  
      A = [0   0   0  2095    2030
 0   2030   2030 2030 2030
 0   0   2095   2055    2065
 2065   2055    2050    2030    2030]
targetval = 2030;
n_rows = size(A,1);
B = zeros(1,n_rows);                      % pre-allocate vector B with a zero for each row of A.
for i = 1:n_rows
    d = A(i,:);
    idx = find(d==targetval, 1, 'first'); % find the first occurrence of targetval in row i.
    if ~isempty(idx)                      % if there is one, store it as element i of B;
        B(i) = idx;                       % (otherwise element i of B remains 0).
    end
end
disp(B);
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