# any returns 0 eventhough there is a non zero element in the row

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Thomas Koelen on 7 Apr 2015
Edited: Thomas Koelen on 7 Apr 2015
I have a cell that looks like this:
measureables =
'GS_L' 'OECF' 'DYNAMIC_RANGE' 'NOISE'
I do this:
OECFINDEX = strcmp(measureables(:,:),'OECF');
which gives:
ans =
0 1 0 0
now I do this:
OECFINDEX = OECFINDEX(:,any(OECFINDEX));
which should give (correct me if I'm wrong): 1
It does work for larger cells that look like this:
measureables =
measureables =
'GS_L' 'OECF' 'DYNAMIC_RANGE' 'NOISE'
'GS_L' 'OECF' 'DYNAMIC_RANGE' 'NOISE'
'GS_L' 'OECF' 'DYNAMIC_RANGE' 'NOISE'
'GS_L' 'DYNAMIC_RANGE' 'NOISE'
here the program gives me:
1
1
1
0
why is not working for a single column?

Thorsten on 7 Apr 2015
Because it's just a vector (or 1 x N matrix),
any(OECFINDEX)
returns a single number, namely 1 in your example, and because OECFINDEX has just one row,
OECFINDEX(:,any(OECFINDEX))
is the same as
OECFINDEX(:,1);
or
OECFINDEX(1)
which is 0 in your case.
Thomas Koelen on 7 Apr 2015
Edited: Thomas Koelen on 7 Apr 2015
Thanks, this answers my question. I made a for loop now to fill an array.

Star Strider on 7 Apr 2015
I believe you’re using the wrong syntax with any.
Consider:
OECFINDEX = [0 0 1 0];
OECFINDEX = any(OECFINDEX)
produces:
OECFINDEX =
1

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