Zero out values in multiple fields of a struct

16 views (last 30 days)
Suppose I have
S.ABC0500 = struct('Keys',[1:9],'Values',rand(1,9));
S.ABC0800 = struct('Keys',[1:9],'Values',rand(1,9));
S.ABC0900 = struct('Keys',[1:9],'Values',rand(1,9));
S.Title = 'MyData';
S.Date = datetime('today');
How can I efficiently set all the values to zero? That is, I want to do
S.ABC0500.Values = zeros(1,9);
S.ABC0800.Values = zeros(1,9);
S.ABC0900.Values = zeros(1,9);
The number of ABC variables is large.
  1 Comment
Stephen23
Stephen23 on 5 May 2023
"How can I efficiently set all the values to zero"
With more suitable data design: don't force meta-data into fieldnames. A non-scalar structure would likely be better:

Sign in to comment.

Accepted Answer

Rich006
Rich006 on 8 May 2023
I have found my own answer, but there's probably a more elegant way.
fn = fieldnames(S); % array of S field names including the ABC variables
idx = regexp(fn,'ABC*'); % cell array of 1 or [] depending on whether fn matches 'ABC*'
for k=1:length(fn)
if idx{k}
S.(fn{k}).Values = zeros(1,9);
end
end
  1 Comment
Matt J
Matt J on 8 May 2023
Edited: Matt J on 8 May 2023
I would simplify this to,
fn = fieldnames(S);
fn=fn( startsWith( fn ,"ABC"));
for k=1:length(fn)
S.(fn{k}).Values(:) = 0;
end
In particular, avoiding repeated calls to zeros() should speed things up a bit.

Sign in to comment.

More Answers (1)

Matt J
Matt J on 5 May 2023
Edited: Matt J on 5 May 2023
I would recommend a different data organization:
S.Title = 'MyData';
S.Date = datetime('today');
S.ID=["ABC0500", "ABC0500", "ABC0900"]';
S.Values=rand(3,9);
S.Keys=repmat(1:9,3,1);
and then you can simply do,
S.Values(:)=0;
  3 Comments
Matt J
Matt J on 8 May 2023
You could do that, but it won't be efficient.
Rich006
Rich006 on 8 May 2023
I guess when I said "efficiently" I meant without having to write a separate command for each variable. I only need to do this one time, so speed of execution isn't that important.

Sign in to comment.

Categories

Find more on Data Type Identification in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!