How to compute the double integral over dx and dy?

Hi, Can someone help me to how to code this equation in matlab? Let x and y are axis of a plane. dx and dy are increments. I have values of a and b at each coordinate(x,y) as shown in the below code.
clear all; close all;clc;
% Let
dx = 0.1;
x = -0.5:dx:0.5;
dy = 0.1;
y = -0.5:dx:0.5;
N = length(x);
a = randn(N,N);
b = randn(N,N);

 Accepted Answer

You are integrating matrices, so use trapz (or cumtrapz, depending on the result you want) once in each dimension —
% clear all; close all;clc;
% Let
dx = 0.1;
x = -0.5:dx:0.5;
dy = 0.1;
y = -0.5:dx:0.5;
N = length(x);
a = randn(N,N);
b = randn(N,N);
columnInt = trapz((a-b).^2) % Column Integrals
columnInt = 1×11
19.6448 26.9404 10.3535 10.6369 19.7843 13.8794 7.4786 12.1139 10.1436 22.0933 19.0884
rowInt = trapz(columnInt) % Integrate Column Integrals
rowInt = 152.7905
totalInt = trapz((trapz((a-b).^2))) % Both In One Line
totalInt = 152.7905
.

2 Comments

Don't forget to scale the results by dx*dy.
I initially forgot that. Assuming ‘x’ defines the columns and ‘y’ defines the rows —
% clear all; close all;clc;
% Let
dx = 0.1;
x = -0.5:dx:0.5;
dy = 0.1;
y = -0.5:dx:0.5;
N = length(x);
a = randn(N,N);
b = randn(N,N);
columnInt = trapz(x,(a-b).^2) % Column Integrals
columnInt = 1×11
3.2512 1.1639 1.0265 1.5750 2.4845 1.1630 3.4526 2.8748 1.7902 0.9262 3.7454
rowInt = trapz(y,columnInt) % Integrate Column Integrals
rowInt = 1.9955
totalInt = trapz(y,trapz(x,(a-b).^2)) % Both In One Line
totalInt = 1.9955
.

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More Answers (2)

Hi Kalasagarreddi,
I understand that you want to compute a double integral.
You can do this with the help of 'integral2' command. Please refer to the following documentation link for information on the syntax of 'integral2'.
Hope this helps!
dx = 0.1;
x = -0.5:dx:0.5;
dy = 0.1;
y = -0.5:dx:0.5;
N = length(x);
a = randn(N,N);
b = randn(N,N);
F = (a-b).^2;
% Use one of the following approximations for the integral
I1 = trapz(y,trapz(x,F,2))
I1 = 2.0996
I2 = trapz(x,trapz(y,F,1))
I2 = 2.0996

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