How can I make an array using for loop?

Hi all!

I am trying to prepare a big array by adding all the cells from Time (18x1 cell array) like this -

TimeSeries = [Time{1,1};Time{2,1};Time{3,1};Time{4,1};Time{5,1};...
    Time{6,1};Time{7,1};Time{8,1};Time{9,1};Time{10,1};...
    Time{11,1};Time{12,1};Time{13,1};Time{14,1};Time{15,1};...
    Time{16,1};Time{17,1};Time{18,1}];

But how can I prepare the TimeSeries array without being too manual about it?

The solution doesn't necessarily have to be a for loop approach. Any other approach is welcome! :)

Answer 1

[Sulaymon Eshkabilov]

It is advised to use timetable instead of timeseries(). Therefore, it is straightforward to create timetable using array2timetable(), e.g.:

A =(1:18)';
AS = seconds(rand(size(A)));                  % Duration 
TT = array2timetable(A, 'RowTimes',AS)        % TimeTable() with 18 rows and two columns

TT = 18×1 timetable
        Time        A 
    ____________    __

    0.37307 sec      1
    0.68903 sec      2
    0.9241 sec       3
    0.19051 sec      4
    0.65233 sec      5
    0.42433 sec      6
    0.25006 sec      7
    0.083402 sec     8
    0.37205 sec      9
    0.37763 sec     10
    0.23997 sec     11
    0.052084 sec    12
    0.54406 sec     13
    0.20393 sec     14
    0.94033 sec     15
    0.55957 sec     16

T = removevars(TT, 'A')                       % 18 by 1 empty TIMETABLE

T =

  18×0 empty timetable

% Alt. way to create timeseries is:
B =(1:18)';
TS = timeseries(B)

  timeseries

  Common Properties:
            Name: 'unnamed'
            Time: [18x1 double]
        TimeInfo: tsdata.timemetadata
            Data: [18x1 double]
        DataInfo: tsdata.datametadata

[Ashfaq Ahmed]

Hi! Thank you for your response but unfortunately, it did not answer my question. I just want to add all the elements from a cell array.

You see, I have here 18 cell array, each of them has many many values (type: double). I want to create a variable that will add ALL these double values in one long matrix. For example -

A{1,1} = [1 2 3]';
A{2,1} = [4 5 6]';
A({3,1} = [7 8 9]';

Now, I want D to be -

D = [A{1,1}; A{2,1}; A{3,1}];

or,

D = [1 2 3 4 5 6 7 8 9]'

D = 9×1

1 2 3 4 5 6 7 8 9

But how can I do it automatically?

[Stephen23]

"Thank you for your response but unfortunately, it did not answer my question."

And yet you have already accepted this answer, which tells everyone that this answer does answer your question. If this does not answer your question, why did you accept this answer?

[Ashfaq Ahmed]

I was trying to communicate with him because I thought I needed to explain my question a bit more.

[Sulaymon Eshkabilov]

As now you question is a bit different from the initial one. if the latter one what you want, this is how one can create a cell array with some values:

M=(1:18).';
T= cell(size(M));   % EMpty cell 18-by-1
for ii = 1:length(M)
    T{ii}=M(ii);    % Cell with elements from M matrix array
end
T

T = 18×1 cell array
    {[ 1]}
    {[ 2]}
    {[ 3]}
    {[ 4]}
    {[ 5]}
    {[ 6]}
    {[ 7]}
    {[ 8]}
    {[ 9]}
    {[10]}
    {[11]}
    {[12]}
    {[13]}
    {[14]}
    {[15]}
    {[16]}

T{:}

ans = 1

ans = 2

ans = 3

ans = 4

ans = 5

ans = 6

ans = 7

ans = 8

ans = 9

ans = 10

ans = 11

ans = 12

ans = 13

ans = 14

ans = 15

ans = 16

ans = 17

ans = 18

[Stephen23]

"I was trying to communicate with him because I thought I needed to explain my question a bit more. "

The only thing that accepting an answer communicates is that you are happy with the information given in that answer. Yet in your very first comment you wrote "Thank you for your response but unfortunately, it did not answer my question". Very confusing.

Answer 2

[Stephen23]

TimeSeries = vertcat(Time{:,1});

https://www.mathworks.com/help/matlab/matlab_prog/comma-separated-lists.html

https://www.mathworks.com/matlabcentral/answers/1656435-tutorial-comma-separated-lists-and-how-to-use-them

[Ashfaq Ahmed]

Omg thank you so much Stephen, look what change you made in my code!!

Haha! That was incredible. Thanks again.