Can you please tell me what is the error ?
3 views (last 30 days)
Show older comments
clc
clear all
E=70*10^6;
v=0.3;
p=50*10^3;
h=0.01;
a=0.5;
b=0.5;
syms x y
B=-h*[6*x*(b-2*y)/(a^(3)*b) 0 (a-6*x)*(b-2*y)/(2*a^2*b) -6*x(b-2*y)/(a^3*b) 0 -(a+6*x)*(b-2*y)/(2*a^2*b) -6*x*(b+2*y)/(a^3*b) 0 -(a+6*x)*(b+2*y)/(2*a^2*b) 6*x*(b+2*y)/(a^3*b) 0 (a-6*x)*(b+2*y)/(2*a^2*b);6*(a-2*x)*y/(a*b^3) -(a-2*x)*(b-6*y)/(2*a*b^2) 0 6*(a+2*x)*y/(a*b^3) -(a+2*x)*(b-2*y)/(2*a*b^2) 0 -6*(a+2*x)*y/(a*b^3) (a+2*x)*(b+6*y)/(2*a*b^2) 0 -6*(a-2*x)*y/(a*b^3) (a-2*x)*(b+6*y)/(2*a*b^2) 0;4*(-3*b^2*x^2+a^2*(b^2-3*y^2))/(a^3*b^3) (b-2*y)*(b+6*y)/(2*a*b^2) -(a-2*x)*(a+6*x)/(2*a^2*b) (12*b^2*x^2-4*a^2*(b^2-3*y^2))/(a^3*b^3) -(b-2*y)*(b+6*y)/(2*a*b^2) -(a-6*x)*(a+2*x)/(2*a^2*b) 4*(-3*b^2*x^2+a^2*(b^2-3*y^2))/(a^3*b^3) -(b-6*y)*(b+2*y)/(2*a*b^2) (a-6*x)*(a+2*x)/(2*a^2*b) (12*b^2*x^2-4*a^2*(b^2-3*y^2))/(a^3*b^3) (b-6*y)*(b+2*y)/(2*a*b^2) (a-2*x)*(a+6*x)/(2*a^2*b)];
0 Comments
Accepted Answer
Karim
on 27 Dec 2022
you forgot a * in -6*x(b-2*y)/(a^3*b) this should be -6*x*(b-2*y)/(a^3*b)
see below
E=70*10^6;
v=0.3;
p=50*10^3;
h=0.01;
a=0.5;
b=0.5;
syms x y
B=-h*[6*x*(b-2*y)/(a^(3)*b) 0 (a-6*x)*(b-2*y)/(2*a^2*b) -6*x*(b-2*y)/(a^3*b) 0 -(a+6*x)*(b-2*y)/(2*a^2*b) -6*x*(b+2*y)/(a^3*b) 0 -(a+6*x)*(b+2*y)/(2*a^2*b) 6*x*(b+2*y)/(a^3*b) 0 (a-6*x)*(b+2*y)/(2*a^2*b);
6*(a-2*x)*y/(a*b^3) -(a-2*x)*(b-6*y)/(2*a*b^2) 0 6*(a+2*x)*y/(a*b^3) -(a+2*x)*(b-2*y)/(2*a*b^2) 0 -6*(a+2*x)*y/(a*b^3) (a+2*x)*(b+6*y)/(2*a*b^2) 0 -6*(a-2*x)*y/(a*b^3) (a-2*x)*(b+6*y)/(2*a*b^2) 0;
4*(-3*b^2*x^2+a^2*(b^2-3*y^2))/(a^3*b^3) (b-2*y)*(b+6*y)/(2*a*b^2) -(a-2*x)*(a+6*x)/(2*a^2*b) (12*b^2*x^2-4*a^2*(b^2-3*y^2))/(a^3*b^3) -(b-2*y)*(b+6*y)/(2*a*b^2) -(a-6*x)*(a+2*x)/(2*a^2*b) 4*(-3*b^2*x^2+a^2*(b^2-3*y^2))/(a^3*b^3) -(b-6*y)*(b+2*y)/(2*a*b^2) (a-6*x)*(a+2*x)/(2*a^2*b) (12*b^2*x^2-4*a^2*(b^2-3*y^2))/(a^3*b^3) (b-6*y)*(b+2*y)/(2*a*b^2) (a-2*x)*(a+6*x)/(2*a^2*b)]
0 Comments
More Answers (0)
See Also
Categories
Find more on Symbolic Math Toolbox in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!