Why am I obtaining incorrect values for Lipschitz 1/2 norms using the central difference method?
1 view (last 30 days)
Show older comments
The Lipschitz 1/2 norm is defined as the maximum value of the absolute value of the derivative of the function over all points in the domain of the function. I have this code that can approximate this value for a given function:
% Define the function f
f = @(x) x.^2;
% Define the domain of the function
x = linspace(-1, 1, 1000);
% Compute the derivative of the function using the central difference method
df = (f(x+1e-8) - f(x-1e-8)) / (2*1e-8);
% Compute the Lipschitz 1/2 norm of the function
lipschitz_norm = max(abs(df));
Here, our function f and linspace for x are just an example.
I am trying to compute the norm for f = @(x) 2*sqrt(1-x), with x = linspace(0, 1, 1000). Or really, f = @(x) c*sqrt(1-x), where c is a real number. Theoretically, it's obvious that the norm for any of these functions is |c|, for a given c. Online, using this code with the example
f = @(x) 2*sqrt(1-x), with x = linspace(0, 1, 1000) gives lipschitz_norm = 2, as it should, but when I run the exact same code on MATLAB on my own, I get 1.4142e+04. I've tried numerous different examples, and my answers have yet to line up. Is there something going on on my end?
1 Comment
Answers (2)
Bjorn Gustavsson
on 22 Dec 2022
You've forgot to take the derivative of the function on-line, and you seem to take some kind of derivative on your own computer. Since the derivative of sqrt(1-x) is 1/2./sqrt(1-x) the max of the absolute goes towards infinity as x aproaches 1 from below.
(Don't worrt, we've all been there)
HTH
0 Comments
Bora Eryilmaz
on 22 Dec 2022
Unless I misunderstodd something, the derivative of
is
.
Within the domain of [0,1], the maximum absolute value of this is +Inf, not 2.
2 Comments
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!