Can we distinguish between variables and parameters in a symbolic function?

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Hello,
I have a simple (perhaps naive, if so my appology) question. Consider the following
syms x f(x) x
f(x) = a*x;
Is there a way to distinguish between 'x' and 'a'? If I use symvar(f) it just gives the information about all vars and aparetly
cannot distinguish between x and a.
Any idea?
Thanks in advance,
Babak
  2 Comments
Dyuman Joshi
Dyuman Joshi on 15 Dec 2022
symvar determines symbolic variables in the expression. Since you have not defined a as a symbolic variable in the above code, symvar won't classify a as an output.
What is the data type of a?

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Accepted Answer

Dyuman Joshi
Dyuman Joshi on 15 Dec 2022
syms f(x) a m n z
f(x)=a*x
f(x) = 
y=symvar(f)
y = 
I understand what you mean by 'cannot distinguish between x and a'
But, this is how syms variable are expressed in arrays. For example -
z=[m n]
z = 
x and a are expressed similarly in the above expression obtained from symvar
However, you can convert the symbolic expression to string and obtain seperate variables -
z=symvar(char(f))
z = 2×1 cell array
{'a'} {'x'}
  6 Comments
Mohammad Shojaei Arani
Mohammad Shojaei Arani on 17 Dec 2022
Hi Torsten and Dyuman,
After I thought deeper I came to believe that you are right. Thanks for your time.
Math is somehow different than programming :-)

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More Answers (1)

Walter Roberson
Walter Roberson on 17 Dec 2022
f_variables = argnames(f)
f_param = setdiff(symvar(f), f_variables)
This is not the same thing as "all variables mentioned that are not parameters". symvar does not report any "bound" variables or any variables being used as functions.
A bound variable is like x in
int(f(x), x, a, b)
provided that f does not itself contain x then you could substitute any other variable name without affecting the output, like
int(f(Dummy), Dummy, a, b)
int() and symsum() and symprod() can all use bound variables.
  1 Comment
Mohammad Shojaei Arani
Mohammad Shojaei Arani on 17 Dec 2022
Hi Torsten,
So, it is actually possible to do it in matlab. Nice!
You also answered another question of me (somehow you read my mind!).
Thanks a lot for the very useful helps!
Babak

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