Trying to make an Adams-Bashforth method with Richardson error estimate

6 views (last 30 days)
%This program solves the initial value problem
% y' = f(x,y), x0 <= x<= b, y(x0)=y0
%Initializing vaiables
%f'(x,y)=
f = @(x,y) cos(y).^2; %derivative in question
g = @(x) atan(x); %this is the actual solution
x0 = 0; %initial value of x
x_end = 10; %end of approximation
h = 0.1; %size of decimal place (0.1,0.001,etc
y0=0; %initial value of y
n = fix((x_end-x0)/h)+1;
x = linspace(x0,x_end,n);
y = zeros(n,1);
y(1) = y0;
f1 = f(x(1),y(1));
y(2) = y(1)+h*f1;
%need to add error
for i = 3:n
f2 = f(x(i-1),y(i-1));
y(i) = y(i-1)+h*(3*f2-f1)/2;
f1 = f2;
fprintf('%5.4f %11.8f\n', x(i), y(i));
plot(x(i),y(i),'b.'); grid on;
fplot(g,[x0,x_end]);
xlabel('x values'); ylabel('y values');
hold on;
end
I'm not sure how I would add the Richardson error to this code. I see the formula in my textbook, but don't understand how I would make it work. . Like I don't really know what that means. I understand the AB method for solving DefEqs, but not ther errors

Answers (1)

Mayank Sengar
Mayank Sengar on 12 Jan 2023
Edited: Mayank Sengar on 12 Jan 2023

Categories

Find more on Programming in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!