i need code in matlab
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(x-a)^2+(y-b)^2=r^2 ,,, the point (a,b) center of circle and (r) the radius ..
with point (-1,3.2) --- (-8,4)--- (-6.5,-9.3)
Accepted Answer
Image Analyst
on 22 Nov 2022
You didn't say what you wanted to do. I'll assume you want to draw the circles on a graph. Here is the code:
x = [-1; -8; -6.5];
y = [3.2; 4; -9.3];
r = 5;
viscircles([x, y], r);
axis equal
grid on
Also see the FAQ:
More Answers (1)
Image Analyst
on 22 Nov 2022
See attached function.
x = [-1; -8; -6.5];
y = [3.2; 4; -9.3];
plot(x, y, 'b.', 'MarkerSize', 50);
% Find the center and radius of a circle going through those points.
[xCenter, yCenter, radius] = circlefit(x, y)
% Display the circle
viscircles([xCenter, yCenter], radius, 'Color', 'r');
axis equal
hold on;
% Plot center with a crosshairs
plot(xCenter, yCenter, 'r+', 'LineWidth', 2, 'MarkerSize', 100);
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