How to fit a data to a model without using Statistical Toolbox?

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For my data (30x2 table), given a model y = a1 + a2 * x^4 + a3 * x^5, I wanted to find the coefficients of my model. I was always directed to linear regression and data fitting which says it needs statistical toolbox but I don't have one. How do I make do of this?
  1 Comment
Mathieu NOE
Mathieu NOE on 7 Nov 2022
hello
for polynomial fit you don't need any specific toolbox
read / look for polyfit / polyval

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Answers (3)

Bruno Luong
Bruno Luong on 14 Nov 2022
Edited: Bruno Luong on 14 Nov 2022
Polynomial fits can be done with linear algebra, no fminsearch is required, but yeah clearly the model cannot fit data with three coefs as stated
% Same data as the Excel file
data=[-0.0834 -0.2409
-0.0826 -0.2405
-0.0775 -0.236
-0.0719 -0.2275
-0.0658 -0.2264
-0.0521 -0.2174
-0.048 -0.2135
-0.04 -0.2127
-0.0279 -0.2064
-0.0266 -0.2062
-0.022 -0.2034
-0.0197 -0.1971
-0.0193 -0.197
-0.0186 -0.1925
-0.0119 -0.1882
-0.0112 -0.1876
-0.0096 -0.166
0.0034 -0.1624
0.0065 -0.1562
0.0108 -0.1551
0.0158 -0.1539
0.0181 -0.1447
0.0312 -0.1422
0.0323 -0.1364
0.036 -0.1214
0.0667 -0.0999
0.0679 -0.0842
0.0734 -0.061
0.0877 -0.0533
0.0884 -0.0503
-0.0834 -0.2409
-0.0826 -0.2405
-0.0775 -0.236
-0.0719 -0.2275
-0.0658 -0.2264
-0.0521 -0.2174
-0.048 -0.2135
-0.04 -0.2127
-0.0279 -0.2064
-0.0266 -0.2062
-0.022 -0.2034
-0.0197 -0.1971
-0.0193 -0.197
-0.0186 -0.1925
-0.0119 -0.1882
-0.0112 -0.1876
-0.0096 -0.166
0.0034 -0.1624
0.0065 -0.1562
0.0108 -0.1551
0.0158 -0.1539
0.0181 -0.1447
0.0312 -0.1422
0.0323 -0.1364
0.036 -0.1214
0.0667 -0.0999
0.0679 -0.0842
0.0734 -0.061
0.0877 -0.0533
0.0884 -0.0503
];
x=data(:,1);
y=data(:,2);
M=x.^[0,4,5];
P=M\y;
a3=P(3);
a2=P(2);
a1=P(1);
P=[a3 a2 0 0 0 a1];
P5 = polyfit(x,y,5);
xi=linspace(min(x),max(x));
ymodel=polyval(P,xi);
yP5=polyval(P5,xi);
close all
h = plot(x,y,'og',xi,ymodel,'-b',xi,yP5,'-r');
legend(h,'data','model with three coefs','Polynomial 5th degree (6 coefs)','location','northwest')

Santosh Fatale
Santosh Fatale on 11 Nov 2022
Hi Decy,
If you have polynomial function for your model and interested to find coefficients from the data, you can use "polyfit" function as follows:
p = polyfit(x, y, n);
Here inouts 'x' and 'y' are your data points and inout 'n' represent the highest degree of the polynomial. The coefficients of polynomial are in variable 'p' and are in descending order of power of independent variable in the polynomial.
For more information about "polyfit" function follow this link:
  2 Comments
Decy
Decy on 12 Nov 2022
Hello. yes, i tried polyfit but the error appeared was this:
Error using ()
Subscripting into a table using one subscript (as in t(i)) is not supported. Specify a row subscript and a variable
subscript, as in t(rows,vars). To select variables, use t(:,i) or for one variable t.(i). To select rows, use t(i,:).

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Mathieu NOE
Mathieu NOE on 14 Nov 2022
hello @Decy
it seems the model choosen is not realy a good match with the data (or vice versa)
here a demo using fminsearch with your specific polynomial model
% load data
data = csvread('data.csv');
x=data(:,1);
y=data(:,2);
%polynomial fit : y = a1 + a2 * x^4 + a3 * x^5
f = @(a1,a2,a3,x) a1 + a2 * x.^4 + a3 * x.^5;
obj_fun = @(params) norm(f(params(1),params(2),params(3),x)-y);
sol = fminsearch(obj_fun, [mean(y),1,1]);
a1_sol = sol(1);
a2_sol = sol(2);
a3_sol = sol(3);
x_fit = linspace(min(x),max(x),100);
y_fit = f(a1_sol, a2_sol, a3_sol, x_fit);
Rsquared = my_Rsquared_coeff(y,f(a1_sol, a2_sol, a3_sol, x)); % correlation coefficient
figure(3);plot(x,y,'o',x_fit,y_fit,'-')
title(['Data fit - R squared = ' num2str(Rsquared)]);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function Rsquared = my_Rsquared_coeff(data,data_fit)
% R2 correlation coefficient computation
% The total sum of squares
sum_of_squares = sum((data-mean(data)).^2);
% The sum of squares of residuals, also called the residual sum of squares:
sum_of_squares_of_residuals = sum((data-data_fit).^2);
% definition of the coefficient of correlation is
Rsquared = 1 - sum_of_squares_of_residuals/sum_of_squares;
end
  1 Comment
Mathieu NOE
Mathieu NOE on 14 Nov 2022
a simple demo to show that the model you want to use would be appropriate if the data would show a S curved shape , like this :
% load data
data = csvread('data.csv');
x=data(:,1);
% y=data(:,2);
% dummy y data
a1 = -0.1743;
a2 = 300;
a3 = 2e4;
y= a1 + a2 * x.^4 + a3 * x.^5 + 0.01*randn(size(x));
%polynomial fit : y = a1 + a2 * x^4 + a3 * x^5
f = @(a1,a2,a3,x) a1 + a2 * x.^4 + a3 * x.^5;
obj_fun = @(params) norm(f(params(1),params(2),params(3),x)-y);
sol = fminsearch(obj_fun, [mean(y),0,0]);
a1_sol = sol(1);
a2_sol = sol(2);
a3_sol = sol(3);
x_fit = linspace(min(x),max(x),100);
y_fit = f(a1_sol, a2_sol, a3_sol, x_fit);
Rsquared = my_Rsquared_coeff(y,f(a1_sol, a2_sol, a3_sol, x)); % correlation coefficient
figure(3);plot(x,y,'o',x_fit,y_fit,'-')
title(['Data fit - R squared = ' num2str(Rsquared)]);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function Rsquared = my_Rsquared_coeff(data,data_fit)
% R2 correlation coefficient computation
% The total sum of squares
sum_of_squares = sum((data-mean(data)).^2);
% The sum of squares of residuals, also called the residual sum of squares:
sum_of_squares_of_residuals = sum((data-data_fit).^2);
% definition of the coefficient of correlation is
Rsquared = 1 - sum_of_squares_of_residuals/sum_of_squares;
end

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