What will be the regex for this type of string?

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Meenal
Meenal on 21 Oct 2022
Answered: Rik on 21 Oct 2022
The regular expression should accept string like:V123456_123456_123456.
  1. String must start with V.
  2. Then any number of digits.
  3. _(underscore) character followed by any number of digits.
  4. Finally an _ character then any number of digits.

Answers (1)

Rik
Rik on 21 Oct 2022
expr = 'V/d*_/d*_/d*';
Or, if 'any' actually means '1 or more':
expr = 'V/d+_/d+_/d+';

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