Finding the sum to n of 1/2^n
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I'm trying to right a code which will output the sum of the series 1/2^n.
Ive used a for loop to iterate n from 1 to 20 for this example
My code keeps outputting 1/2^20 as the answer, instead of 1/2 + 1/2^2 + 1/2^3 ... +1/2^20
Here is my code
n = 0;
for n = 1:20
b = 1./(2.^n);
end
Sn = sum(b);
disp(Sn)
What am i doing wrong?
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Answers (2)
Davide Masiello
on 12 Oct 2022
You haven't indexed the loop variable
for n = 1:20
b(n) = 1./(2.^n);
end
Sn = sum(b);
disp(Sn)
You can also do it without loop
n = 1:20;
b = sum(1./(2.^n))
1 Comment
Davide Masiello
on 12 Oct 2022
Edited: Davide Masiello
on 12 Oct 2022
Of course, if you need the series to start from n=0, just replace n = 1:20 with n = 0:20. That also means you can't use n as loop iteration index, so you change to
n = 0:20;
for i = 1:length(n)
b(i) = 1./(2.^n(i));
end
Sn = sum(b);
disp(Sn)
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