form a row vector

I have to form a row vector x=[5 6 16 17 27 28 38 39....] till the total number of elements become 'n' where 'n' is entered by the user. Say, I enter n=4 so my x=[5 6 16 17]

basically what I want is that if I have two numbers say, X and Y and I wish to give some increment to these numbers to form a row matrix containing 'n' elements. Say, increment is 3 and n is 6 A=[X Y X+3 Y+3 X+6 Y+6]

[akshata k]

for i=1:n

    x1(1,n)=x(1,n);
end

Answer 1

[Michael Haderlein]

First, get all the X+... and Y+... separately and get them into the correct order then (Activate the commented % to stop the output as it's only for educational reasons here):

>> inc=11;X=5;Y=6;
>> N=3;
>> Z=[X+(0:N-1)*inc;Y+(0:N-1)*inc] %;  %first row: X+..., second row: Y+...

Z =

       5    16    27
       6    17    28

>> Z(:)'

ans =

       5     6    16    17    27    28

[Ace_ventura]

Thanks Michael.

[Stephen Cobeldick]

To get the output to be length N, as the original question requested, try this:

>> inc = 11;
>> X = 5;
>> Y = 6;
>> N = 3;
>> Z = inc*(0:N/2);
>> Z = [X+Z; Y+Z];
>> Z = Z(1:N);

Answer 2

[Chandrasekhar]

x = [5 6 16 17 27 28 38 39....] 
n = input('enter the total number of elements');
x = x[1:n];
disp(x);

[Ace_ventura]

I don't think it will work.Can we define x the way you have defined?

[Ace_ventura]

basically what I want is that if I have two numbers say, X and Y and I wish to give some increment to these numbers to form a row matrix containing 'n' elements. Say, increment is 3 and n is 6 A=[X Y X+3 Y+3 X+6 Y+6]

[Jan]

@Jeff: What have you tried so far and which problems occur? It is much easier to answer, if you show us what you have done so far.

[Ace_ventura]

 x=5;y=6;
a=(x:2:10);
A=a';
b=(y:2:11);
B=b';
c=horzcat(A,B)

c =

     5     6
     7     8
     9    10

>> d=c(:)'

d =

     5     7     9     6     8    10
but now I have got it