How to find distance using loop?

Hi everyone,

I have to find the distance between IRS and users in 3D, for example from IRS 1 to user1, user2, user 3, user 4 and then from IRS 2 to all the users and so on. I have total 4 users and 8 IRS, I found the distances for each one using norm but now I want to find the distances using a loop so how will the loop work? New to using Matlab and I'm a little bit lost with it. Any answers would be appreciated.

%Distance of IRSs from all the users

IRS1U1=norm([3,1.5,1.5]-[6,8,1])

IRS1U2=norm([3,1.5,1.5] - [6,3,1.5])

IRS1U3=norm([3,1.5,1.5] - [6.5,5.5,1.5])

IRS1U4=norm([3,1.5,1.5] - [9,5.5,1.5])

IRS2U1=norm([6,1,1.5]-[6,8,1])

IRS2U2=norm([6,1,1.5] - [6,3,1.5])

IRS2U3=norm([6,1,1.5] - [6.5,5.5,1.5])

IRS2U4=norm([6,1,1.5] - [9,5.5,1.5])

IRS3U1=norm([8.5,1,1.5]-[6,8,1])

IRS3U2=norm([8.5,1,1.5] - [6,3,1.5])

IRS3U3=norm([8.5,1,1.5] - [6.5,5.5,1.5])

IRS3U4=norm([8.5,1,1.5] - [9,5.5,1.5])

IRS4U1=norm([10.4,2,1.5]-[6,8,1])

IRS4U2=norm([10.4,2,1.5] - [6,3,1.5])

IRS4U3=norm([10.4,2,1.5] - [6.5,5.5,1.5])

IRS4U4=norm([10.4,2,1.5] - [9,5.5,1.5])

IRS5U1=norm([3,10.5,1.5]-[6,8,1])

IRS5U2=norm([3,10.5,1.5] - [6,3,1.5])

IRS5U3=norm([3,10.5,1.5] - [6.5,5.5,1.5])

IRS5U4=norm([3,10.5,1.5] - [9,5.5,1.5])

IRS6U1=norm([6,10.5,1.5]-[6,8,1])

IRS6U2=norm([6,10.5,1.5] - [6,3,1.5])

IRS6U3=norm([6,10.5,1.5] - [6.5,5.5,1.5])

IRS6U4=norm([6,10.5,1.5] - [9,5.5,1.5])

IRS7U1=norm([8.5,10.5,1.5]-[6,8,1])

IRS7U2=norm([8.5,10.5,1.5] - [6,3,1.5])

IRS7U3=norm([8.5,10.5,1.5] - [6.5,5.5,1.5])

IRS7U4=norm([8.5,10.5,1.5] - [9,5.5,1.5])

IRS8U1=norm([10.5,9,1.5]-[6,8,1])

IRS8U2=norm([10.5,9,1.5] - [6,3,1.5])

IRS8U3=norm([10.5,9,1.5] - [6.5,5.5,1.5])

IRS8U4=norm([10.5,9,1.5] - [9,5.5,1.5])

Answer 1

[rumin diao]

you can use two loops:

dist = zeros(8,4); % the matrix to save distances
for i = 1 : 8 % use this loop to get IRS1-IRS8
    for j = 1 : 4 % use this loop to get 4 users
        %calculate distance and save it to matrix
        dist(i,j) = norm();% you can fill in the statement cause im not sure the meaning of arrays you use in 'norm';
    end
end

[Zarghuna Suhail]

d =zeros(IRS_max,U_max); % the matrix to save distances

for i = 1 : IRS_max

for j = 1 : U_max

d(i,j)=sum(sqrt(IRS(:,i).^2+Users(:,j).^2));

end

end

I used this and it is giving a matrix of 8 by 4 but the distances are different from the ones calculated using norm individually..

[rumin diao]

the d(i,j) you want maybe is:

sqrt(sum((IRS(:,i) - Users(:,j)).^2))

you can have a try

[Zarghuna Suhail]

It worked , thanks alot!