To find n number of histcounts in a loop
    5 views (last 30 days)
  
       Show older comments
    
Hi,
I am having a cell array (c) of 3000*2 cell, each containing 1*1000 matrix values. Here I need to find histcounts of each cell and concatenate horizontally. I have used following code to calculate individually, but I need to do for all 3000*2 cell in a loop and store it in a separate cell array (z) of dimension 3000*30. (since bin count is 15 for each column).
[N{1},edges{1}] = histcounts(c{1,1},15); % bin count=15 % column 1
[N{2},edges{2}] = histcounts(c{1,2},15); % column 2
z = horzcat(N{1,1}, N{1,2}); %horizontal concatenation
How can I do this? Kindly help me with this. Thanks in advance.
0 Comments
Accepted Answer
  KSSV
      
      
 on 14 Jul 2022
        
      Edited: KSSV
      
      
 on 14 Jul 2022
  
      z = cell2mat(N) ; 
Or
z = [N{:}] ;
4 Comments
  KSSV
      
      
 on 14 Jul 2022
				Are you looking for?
[m,n] = size(c) ; 
z = cell(m,1) ; 
for i = 1:m
    [N{1},edges{1}] = histcounts(c{i,1},15); % bin count=15 % column 1
    [N{2},edges{2}] = histcounts(c{i,2},15); % column 2
    z{i} = horzcat(N{1,1}, N{1,2}); %horizontal concatenation
end
More Answers (0)
See Also
Categories
				Find more on Characters and Strings in Help Center and File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!