Divideind not working in r2014a

I have data file of 200*62 and i have to split it for training validation and testing (not randomly). So im using divideind function but not able to run the code as im having this error. Looking forward to some help . Thanks in advance here is my code :

inputs = input;

targets = out_final; hiddenLayerSize = 10;

net = patternnet(hiddenLayerSize);

trainInd = 1:100;

valInd = 101:150;

testInd = 151:200;

Q=200;

net.divideFcn='divideind'; %%%here is the error line 21

net.divideParam.trainInd=trainInd;

net.divideParam.valInd=valInd;

net.divideParam.testInd=testInd;

% Train the Network

[net,tr] = train(net,inputs,targets);

% Test the Network

outputs = net(inputs);

errors = gsubtract(targets,outputs);

performance = perform(net,targets,outputs);

% View the Network

view(net)

Error message :

Error in network/subsasgn (line 13) net = network_subsasgn(net,subscripts,v,netname);

Error in div (line 21) net.divideFcn='divideind';

[Greg Heath]

 How many classes?

 What are the dimensions of the input and target?

 size(inputs) = ?

 size(targets) = ?

 cell or double?

 I ran your code using the iris data set without error.

 Try all of the divide functions to see if any of them work.

Hope this helps.

Greg

[Sandeep]

hi, thank you for your reply.

input is 62*200

targets is 5*200

5 classes totally

All other divide functions were working Except "divideind"

divideind also worked in an other system but not in mine. This is Bizzare

[Greg Heath]

Hi ,

Thank you for your help. It was really helpfull and i could fix my problem. My another doubt is that is it possible to get value of performance greater than 1?

In my code i'm getting values greater than 1. Can u please me suggest me if i'm right or wrong? Code for you reference is in the below link.

http://www.mathworks.com/matlabcentral/answers/175162-divideind-not-working-in-r2014a

Thanks Sandeep

 >> net = patternnet;
   performFcn = net.performFcn

 performFcn = crossentropy

>> help crossentropy
    doc crossentropy
   type crossentropy

!!!!!!!!!!!!!!!!!!! BUG !!!!!!!!!!!!!

The documentation does not give the formula!

Search NEWSGROUP and ANSWERS using

 greg crossentropy

to find which formula is being used.

Hope this helps.

Greg

[Sandeep]

Thank you so much. Also can you tell me if my code also performs validation and testing on the divided indices?

Or do i have to separately use a different function to perform validation and testing?

Thanks in advance

Sandeep

[Greg Heath]

No. It is automatic. You can figure it yourself from the training record if you first type, without semicolon

 tr = tr

Hope this helps.

Greg

[Sandeep]

Thank you so much for the response. really really helpful.